SQL Query显示所有列

Question

我有下表和一个SQL查询来确定表中的任何商品的购买价格是否高于卖价。

查询：

SELECT id, name 
FROM orders 
GROUP BY id, name 
HAVING MAX(CASE WHEN buy = 'false' THEN price END) > MIN(CASE WHEN buy = 'true' THEN price END)

问题是这只返回两行：

我正在寻找的结果应该显示购买价格高于所有列的卖价的所有商品。阅读GROUP BY我发现它只返回不同的值。我是否必须使用连接来实现最终结果？

|id  |buy   |date                    |price |name
 --------------------------------------------------
 3    false  2017-01-04 19:23:12.000  7      bread
 3    false  2017-01-04 19:23:12.000  4      bread
 2    false  2017-01-04 19:23:12.000  7      grapes

使用此查询的结果是下面的表格，红色突出显示的行不应该在那里。

SELECT * 
FROM orders 
WHERE id IN (SELECT id 
             FROM orders 
             GROUP BY id, name 
             HAVING MAX(CASE WHEN buy = 'false'  THEN price END) > MIN(CASE WHEN  buy = 'true' THEN price END))

Answer 1

将现有查询用作子查询：

SELECT * from orders where id in 
(
    SELECT id 
    FROM orders 
    GROUP BY id, name 
    HAVING MAX(CASE WHEN buy = 'false'  THEN price END) > MIN(CASE WHEN buy = 'true' THEN price END)
)