Question

我有一个特定的字符串，如下所示

*WTY:   but the light of the dining room suddenly turn off .
%mor:   conj|but det|the n|light prep|of det|the adj|dining n|room adv|suddenly v|turn adv|off .
%snd:   <00:14:74><00:25:53>
%WTY:   {and} rpl but {suddenly} rpl (0.43) {the} * (1.07) {the light (0.78) suddenly turn off and} # (1.24) the light of the dining room suddenly turn off . err_m_s err_m_l ::: |

我想提取圆括号（）内的数字并计算所有这些数字的总和。我已经尝试了以下RegEx来提取数字，但它没有返回任何结果。

str.match(/\((\d+)\)/)

Answer 1

你可以试试这个：

/\((\d*\.?\d*)\)/g

Explanation

＆＃13;

const regex = /\((\d*\.?\d*)\)/g;
const str = `*WTY:   but the light of the dining room suddenly turn off .
%mor:   conj|but det|the n|light prep|of det|the adj|dining n|room adv|suddenly v|turn adv|off .
%snd:   <00:14:74><00:25:53>
%WTY:   {and} rpl but {suddenly} rpl (0.43) {the} * (1.07) {the light (0.78) suddenly turn off and} # (1.24) the light of the dining room suddenly turn off . err_m_s err_m_l ::: |`;
let m;

var val=0.0;
while ((m = regex.exec(str)) !== null) {
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    //console.log(m[1]);
    val+=parseFloat(m[1]);
}
console.log(val);

＆＃13;

在接受的答案中填写您的评论

如果我只计算括号的总和，那还有一件事在：; :(包括：;：a，：;：b，：;：a）之前或之后。

你可以申请这个正则表达式：

:;:\s*\((\d*\.?\d*)\)|\((\d*\.?\d*)\)\s*:;:

＆＃13;

const regex = /:;:\s*\((\d*\.?\d*)\)|\((\d*\.?\d*)\)\s*:;:/g;
const str = `*WTY:   but the light of the dining room suddenly turn off .
%mor:   conj|but det|the n|light prep|of det|the adj|dining n|room adv|suddenly v|turn adv|off .
%snd:   <00:14:74><00:25:53>
%WTY:   {and} rpl but {suddenly} rpl  :;: (0.43) {the} * (1.07) :;: {the light (0.78) suddenly turn off and} # (1.24) the light of the dining room suddenly turn off . err_m_s err_m_l ::: |`;
let m;

var val=0.0;
while ((m = regex.exec(str)) !== null) {
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
  if(typeof m[1] !== 'undefined')
    val+=parseFloat(m[1]);
  else
     val+=parseFloat(m[2]);
    //val+=parseFloat(m[1]);
}
console.log(val);

＆＃13;

Answer 2

您没有结果的主要原因是您没有考虑数字中的点，因此您会错过所有非整数数字。一旦你纠正了这个，你仍然只得到一个结果，因为你没有在正则表达式中指定全局修饰符（g）。

您可以使用此三步转换：

const sum = s.match(/\([\d.]+(?=\))/g) // get the numbers
             .map( a => +a.substr(1) ) // remove opening parenthesis and convert to number
             .reduce( (a,b) => a+b );  // total them

演示：

＆＃13;

const s = `*WTY:   but the light of the dining room suddenly turn off .
%mor:   conj|but det|the n|light prep|of det|the adj|dining n|room adv|suddenly v|turn adv|off .
%snd:   <00:14:74><00:25:53>
%WTY:   {and} rpl but {suddenly} rpl (0.43) {the} * (1.07) {the light (0.78) suddenly turn off and} # (1.24) the light of the dining room suddenly turn off . err_m_s err_m_l ::: |`;

const sum = s.match(/\([\d.]+(?=\))/g) // get the numbers
             .map( a => +a.substr(1) ) // remove opening parenthesis and convert to number
             .reduce( (a,b) => a+b );  // total them

console.log(sum.toFixed(2));

＆＃13;

注意：对.toFixed的调用是可选的，但它解决了floating point inaccuracies可能遇到的问题。

计算字符串中括号内的数字

2 个答案: