如何根据日期从mysql数据库中获取数据？

Question

我有一个名为clients的Mysql表，其中一个名为conn_date的字段包含客户注册日期。

现在我想从此表中获取conn_date大于注册日期且小于当前日期的数据。

例如如果用户在2016-06-01上注册，则所有数据都应返回coon_date大于2016-06-01且小于当前日期

conn_date列值

2016-06-01
2016-08-30
2016-08-30
2016-07-01
2016-08-03
2016-09-18

Mysql查询

$get_client = "SELECT SUM(cbp.pay_amount) AS total_pay_amount, SUM(cbp.discount_amount) AS total_discount_amount, SUM(cbp.advance_amount) AS total_advance_amount, SUM(cbp.due_amount) AS total_due_amount, cbp.advance_amount, cbp.bill_month, YEAR(cbp.bill_month) AS myBillYear, MONTH(cbp.bill_month) AS myBillMonth, cbp.cbp_id, cbp.due_amount, cbp.pay_amount, c.conn_date, c.status, c.client_id, c.monthly_bill, c.user_id, c.address, c.contact_no, zone.zone_name, package.package_name, c.bill_date FROM clients AS c 
LEFT JOIN zone ON zone.zone_id = c.zone_id 
LEFT JOIN package ON package.package_id = c.package_id 
LEFT JOIN clients_pay_bill AS cbp ON cbp.client_id = c.client_id 
WHERE c.uid = '$uid' AND c.conn_date <= CURDATE() ";

if($selected_zone != "all") {
    $get_client .= " AND c.zone_id != '' ";
} elseif($selected_zone == "all") {
    $get_client .= " AND c.zone_id != '' ";
} else {
    $get_client .= " AND c.zone_id = '$selected_zone' ";
}

$get_client .= " GROUP BY c.client_id ORDER BY c.client_id DESC ";

现在它只显示当前月份数据不超过注册日期！

Answer 1

尝试使用以下查询：

它将返回2016-06-01和current date之间的数据记录。

select * from clients where conn_date < CURDATE() and conn_date > '2016-06-01'