在PostgreSQL

Question

我想在PostgreSQL中将行转换为列。我希望所有变量都针对各自的id.but它不起作用。

预期输出：

myvar   desc    fname   lname        sdate          edate         id     
title1  desc1   cina    jhon    1483920000000   1484524800000     14
title2  desc2   jhon    lname2  1483920000000   1483910000000     16
title3  desc3   diesel  zier    1483920000000   1484524800000     17



 SELECT * FROM crosstab(
 'SELECT  name, value, id FROM test ORDER  BY id') AS (
 "myVar" text, "desc" text, "fname" text, "lname" text,"sdate" text,"edate" text, "value" text ,"containerid" bigint);

错误：     错误：返回类型无效     SQL状态：42601     详细信息：SQL rowid数据类型与返回的rowid数据类型不匹配。

Answer 1

也许这会有所帮助。

此处需要

ORDER BY 1,2。

select *
    from crosstab (
        'select id, name, value
        from tt1
        order by 1,2')
    AS (row_name int, col1 text, col2 text, col3 text, col4 text);

+----------+-------+--------+--------+--------+
| row_name | col1  |  col2  |  col3  |  col4  |
+----------+-------+--------+--------+--------+
|    14    | desc1 |  chen  |  john  | title1 |
+----------+-------+--------+--------+--------+
|    15    | desc2 | fname2 | lname2 | title2 |
+----------+-------+--------+--------+--------+
|    16    | desc4 | deiser |  ziel  | title3 |
+----------+-------+--------+--------+--------+

实际上，列应命名为：col1，col2，col3，col4，...

在此处查看：http://rextester.com/MFWAW58518