Question

我想在我的应用中创建通知，这将在10秒内显示。它在应用程序运行时运行良好，但是当我关闭应用程序时，不会显示通知。这是我的代码：

我的通知服务：

ocamlopt -c tests.ml

类，它会启动通知：

[Service]
class NotifyEvent : IntentService
{
    protected override void OnHandleIntent(Intent intent)
    {

        PendingIntent pIntent = PendingIntent.GetActivity(this, 0, intent, 0);

        Notification.Builder builder = new Notification.Builder(this);
        builder.SetContentTitle(Resources.GetString(Resource.String.NotifikaceNadpis));
        builder.SetContentText(Resources.GetString(Resource.String.NotifikaceText));
        builder.SetSmallIcon(Resource.Drawable.Icon);
        builder.SetPriority(1);
        builder.SetDefaults(NotificationDefaults.Sound | NotificationDefaults.Vibrate);
        builder.SetWhen(Java.Lang.JavaSystem.CurrentTimeMillis());
        Notification notifikace = builder.Build();

        NotificationManager notificationManager = GetSystemService(Context.NotificationService) as NotificationManager;

        const int notificationId = 0;
        notificationManager.Notify(notificationId, notifikace);
    }
}

活动方法：

public class Notificator
{
    public void ShowNotification(Context context)
    {
        Intent intent = new Intent(context, typeof(NotifyEvent));
        var pendingServiceIntent = PendingIntent.GetService(context, 0, intent, PendingIntentFlags.UpdateCurrent);

        AlarmManager alarm = (AlarmManager)context.GetSystemService(Context.AlarmService);

        alarm.Set(AlarmType.ElapsedRealtimeWakeup, SystemClock.ElapsedRealtime() + 10000, pendingServiceIntent);
    }
}

我的活动：

Notificator not = new Notificator();
not.ShowNotification(this);

感谢您的帮助。

Answer 1

你可以试试这个。

<div class="form-group">
                <label>Time Schedule:</label>
                <div id="items">
                <div class="col-md-4">
                    <input type="text" class="form-control" name="name" placeholder="12:00" data-timepicker>
                    </div> 
                    <div class="col-md-2"><h5>TO</h5></div>
                    <div class="col-md-4">
                    <input type="text" class="form-control" name="name" placeholder="12:00" data-timepicker>
                    </div>
                 </div>
            </div>

Answer 2

当您销毁应用程序时，应该保持服务的活动。

在return StartCommandResult.Sticky;方法中添加OnStartCommand。
启动服务OnTaskRemoved功能。

使用Service界面创建服务，IntentService用于耗时的操作。

 class NotifyEvent : Service
    {
        [return: GeneratedEnum]
        public override StartCommandResult OnStartCommand(Intent intent, [GeneratedEnum] StartCommandFlags flags, int startId)
        {
            new Task(() => {

                PendingIntent pIntent = PendingIntent.GetActivity(this, 0, intent, 0);
                Notification.Builder builder = new Notification.Builder(this);
                builder.SetContentTitle("hello");
                builder.SetContentText("hello");
                builder.SetSmallIcon(Resource.Drawable.Icon);
                builder.SetPriority(1);
                builder.SetDefaults(NotificationDefaults.Sound | NotificationDefaults.Vibrate);
                builder.SetWhen(Java.Lang.JavaSystem.CurrentTimeMillis());
                Notification notifikace = builder.Build();
                NotificationManager notificationManager = GetSystemService(Context.NotificationService) as NotificationManager;
                const int notificationId = 0;
                notificationManager.Notify(notificationId, notifikace);

            }).Start();
            return StartCommandResult.Sticky;
        }

        public override IBinder OnBind(Intent intent)
        {
            return null;
        }
        public override void OnTaskRemoved(Intent rootIntent)
        {
            Intent restartService = new Intent(ApplicationContext, typeof(NotifyEvent));
            restartService.SetPackage(PackageName);
            var pendingServiceIntent = PendingIntent.GetService(ApplicationContext, 0, restartService, PendingIntentFlags.UpdateCurrent);
            AlarmManager alarm = (AlarmManager)ApplicationContext.GetSystemService(Context.AlarmService);
            alarm.Set(AlarmType.ElapsedRealtime, SystemClock.ElapsedRealtime() + 1000, pendingServiceIntent);

            System.Console.WriteLine("service OnTaskRemoved");
            base.OnTaskRemoved(rootIntent);
        }
    }

Android Xamarin - 关闭应用程序通知

2 个答案: