Question

我有一个python脚本，在单个代码部分，必须执行一个终端命令，这是代码：

# run shell script and return response printed
def run_shell(command_string):
    p = subprocess.Popen([command_string], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
    return p.communicate()

它是获取命令并运行该命令的特定功能。例如，当输入是＆＃34;找到＆＃34; （以递归方式列出文件和目录）输出是：

./actions
./actions/scripts
./actions/scripts/script_aa00.py
./log_list_template.json
./README.md
./.git
./main
./main/Classifier.py
./main/Solver.py
./main/learner.py
./main/Database.py
./main/__pycache__
./main/__pycache__/Database.cpython-35.pyc
./main/__pycache__/learner.cpython-35.pyc
./start.sh
./run.py
./signals
./signals/scripts
./signals/scripts/script_aa00.py  [I want to run this script]
./signals/list0.json
./signals/template.json

但是当输入是＆＃34; python3 signals / scripts / script_aa00.py ＆＃34;输出包含一个错误，表示找不到script_aa00.py。当我尝试＆＃34; python3 signals / scripts / script_aa00.py ＆＃34;我在终端（在这个目录中）工作正常

Answer 1

您可以尝试将shell=true添加到Popen和/或使用绝对路径：

p = subprocess.Popen(['/usr/bin/python3', '/home/.../signals/scripts/script_aa00.py'], shell=true, stdout=subprocess.PIPE, ...)

通过python运行shell脚本中找不到文件

1 个答案: