Question

我有一个包含多个列的mysql表。使用php我想在html表中显示结果。到目前为止一切都那么好，但是我想在一行中显示name_of_insurance和金额，但是根据month_of_payment不同的列数。

mysql / php代码：

<html>
<head>
<title>Monatsübersicht</title>
<link href="design.css" type="text/css" rel="stylesheet">
</head>
<?php
include 'connect.php';
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
$sql = "SELECT name_of_insurance, amount, month_of_payment FROM insurance     where active = 'on'";
$result = mysqli_query($link, $sql);

if (mysqli_num_rows($result) > 0) {
// output data of each row
echo "<table><tr><th>Name</th><th>Jan</th><th>Feb</th><th>März</th><th>Apr</th><th>Mai</th><th>Jun</th><th>Jul</th><th>Aug</th><th>Sep</th><th>Okt</th><th>Nov</th><th>Dez</th></tr>";
 // output data of each row
 while($row = $result->fetch_assoc()) {
     echo "<tr><td>" . $row["name_of_insurance"]. "</td><td>" .     $row["amount"]. "</td></tr>";
 }
 echo "</table>";    
} else {
echo "0 results";
}
mysqli_close($link);

?>

</html>

如何将结果放在具有多个查询或$ result的不同列中？

提前致谢。 BR 弗洛里安

Answer 1

假设 month_of_payment 列值为Jan, Feb, März等格式，问题的解决方案将是这样的：

创建一个月份数组，其中包含 month_of_payment 列中所有可能的月份值，如下所示：

$monthArr = array('Jan', 'Feb', 'März', 'Apr', 'Mai', 'Jun', 'Jul', 'Aug', 'Sep', 'Okt', 'Nov', 'Dez');

现在在while循环的每次迭代中，创建一个for循环来检查哪个月$row["month_of_payment"]值落入并显示在相应的表格单元格中，如下所示：

while($row = $result->fetch_assoc()) {
    echo "<tr><td>" . $row["name_of_insurance"]. "</td>";
    for($i = 0; $i < $count; ++$i){
        echo "<td>";
        if($row["month_of_payment"] == $monthArr[$i]){
            echo $row["amount"];
        }
        echo "</td>";
    } 
    echo "</tr>";
}

其中$count是$monthArr数组中的元素/月数，即$count = count($monthArr);

这是完整代码：

<html>
<head>
    <title>Monatsübersicht</title>
    <link href="design.css" type="text/css" rel="stylesheet">
</head>
<body>
<?php
    include 'connect.php';
    // Check connection
    if($link === false){
    die("ERROR: Could not connect. " . mysqli_connect_error());
    }
    $sql = "SELECT name_of_insurance, amount, month_of_payment FROM insurance where active = 'on'";
    $result = mysqli_query($link, $sql);

    $monthArr = array('Jan', 'Feb', 'März', 'Apr', 'Mai', 'Jun', 'Jul', 'Aug', 'Sep', 'Okt', 'Nov', 'Dez');
    $count = count($monthArr);
    if (mysqli_num_rows($result) > 0) {
        // output data of each row
        echo "<table><tr><th>Name</th><th>Jan</th><th>Feb</th><th>März</th><th>Apr</th><th>Mai</th><th>Jun</th><th>Jul</th><th>Aug</th><th>Sep</th><th>Okt</th><th>Nov</th><th>Dez</th></tr>";
        while($row = $result->fetch_assoc()) {
            echo "<tr><td>" . $row["name_of_insurance"]. "</td>";
            for($i = 0; $i < $count; ++$i){
                echo "<td>";
                if($row["month_of_payment"] == $monthArr[$i]){
                    echo $row["amount"];
                }
                echo "</td>";
            } 
            echo "</tr>";
        }
        echo "</table>";    
    } else {
        echo "0 results";
    }
    mysqli_close($link);
?>
</body>
</html>

Answer 2

感谢Rajdeep Paul：我的问题的正确答案如下：

<html>
<head>
<title>Monatsübersicht</title>
<link href="design.css" type="text/css" rel="stylesheet">
</head>
<body>
<?php
include 'connect.php';
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
$sql = "SELECT name_of_insurance, amount, month_of_payment FROM insurance where active = 'on'";
$result = mysqli_query($link, $sql);

$monthArr = array('jan', 'feb', 'mar', 'apr', 'may', 'jun', 'jul', 'aug', 'sep', 'oct', 'nov', 'dec');
$count = count($monthArr);
if (mysqli_num_rows($result) > 0) {
    // output data of each row
    echo "<table><tr><th>Name</th><th>Jan</th><th>Feb</th><th>März</th><th>Apr</th><th>Mai</th><th>Jun</th><th>Jul</th><th>Aug</th><th>Sep</th><th>Okt</th><th>Nov</th><th>Dez</th></tr>";
    while($row = $result->fetch_assoc()) {
        echo "<tr><td>" . $row["name_of_insurance"]. "</td>";
        for($i = 0; $i < $count; ++$i){
            echo "<td>";
            if($row["month_of_payment"] == $monthArr[$i]){
                echo $row["amount"];
            }
            echo "</td>";
        } 
        echo "</tr>";
    }
    echo "</table>";    
} else {
    echo "0 results";
}
mysqli_close($link);
?>
</body>
</html>

将mysql的结果放到同一行

2 个答案: