Question

我试图以下面的格式从MYSQL查询中获取结果

Date: '2016-01-01', Resource_1: 100, Resource_2: 90, Resource_3:30, Resource_4: 20
Date: '2016-01-02', Resource_1: 0, Resource_2: 20, Resource_3:100, Resource_4: 40
Date: '2016-01-03', Resource_1: 70, Resource_2: 40, Resource_3:0, Resource_4: 50
Date: '2016-01-04', Resource_1: 10, Resource_2: 0, Resource_3:30, Resource_4: 0

我的MYSQL结果采用以下格式：

2016-01-01|Resource_1|100
2016-01-01|Resource_2|90
2016-01-01|Resource_3|30
2016-01-01|Resource_4|20
2016-01-02|Resource_1|0
2016-01-02|Resource_2|20
2016-01-02|Resource_3|100
2016-01-02|Resource_4|40
2016-01-03|Resource_1|70
2016-01-03|Resource_2|40   
2016-01-03|Resource_3|0
2016-01-03|Resource_4|50
2016-01-04|Resource_1|10
2016-01-04|Resource_2|0
2016-01-04|Resource_3|30
2016-01-04|Resource_4|0

如何在MYSQL中将其转换为所需的格式。

我想提一下我的表格结构如下：

DATE|RESOURCE_NAME|MARKS

我使用以下查询来获取先前的查询结果

SELECT cd.cd_claim_dt AS cdt,res.res_Name AS NAME,
SUM(CASE WHEN MONTH(cd.cd_claim_dt) = 1 AND YEAR(cd.cd_claim_dt) = 2016 THEN    
ct.ct_duration ELSE 0 END) claimed_hrs
FROM 
tbl_claim_data cd, tbl_claim_time ct, tbl_resourceinfo res
WHERE 
ct.cd_slno = cd.cd_slno AND MONTH(cd.cd_claim_dt) = 1 AND   
YEAR(cd.cd_claim_dt) = 2016 AND cd.app_SlNo = 35 AND 
cd.res_slno IN(17,22,23,24) AND res.res_SlNo = cd.res_slno
GROUP BY 
cd.res_slno, cd.cd_claim_dt, cd.cd_status
ORDER BY 
cd.cd_claim_dt

Answer 1

尝试此查询

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您还可以使用 concat_ws（） instandof concat（）功能

将mysql查询结果格式化为所需格式

1 个答案: