Question

#include <iostream>
#include <math.h>

using namespace std;

int Square(int num, int& Answer);
int Triangle(int num);

int main(int argc, char **argv)
{
    int num = -1;
    int Answer;
  //Prompts the user for the length of the sides and doesnt stop until they     enter a valid input
while(num >= 6 || num <= 1){
    cout<<"Enter a number from 1 to 6: ";

    cin>>num;
    }

Square(int num, int& Answer);
Triangle(int num, int&Answer);


}

int Square(int num, int& Answer){
    Answer = num * num;
    cout<<Answer;
}

int Triangle(int num, int& Answer){
    Answer = .5 * (num * num);
    cout<<Answer;
}

我不确定我做错了什么，但我一直在犯的错误是，预期在＆＃39; int＆＃39;

之前的初级表达

这是错误的位置，它出现在每个int

的实例上

Square(int num, int& Answer);
Triangle(int num, int&Answer);

Answer 1

这不是如何调用函数：

Square(int num, int& Answer);
Triangle(int num, int&Answer);

更正：

Square  (num, Answer);
Triangle(num, Answer);

还包括cmath而不是math.h：
```
#include <cmath>
```
函数三角形也只接受一个参数，你传递两个参数：
```
Triangle(int num, int&Answer);
```

所以要么传递num或回答。

另一件事：为什么将Answer作为参数传递？

您只能传递num，每个函数的返回值将其存储在Answer中。一个例子是这样的：

#include <iostream>
//#include <cmath> // if you don't need it don't include it
using namespace std;

int Square  (int num); // Square needs only parameter and returns the result in return value
int Triangle(int num); // the same as above

int main(int argc, char **argv)
{
    int num = -1;
    int Answer;
  //Prompts the user for the length of the sides and doesnt stop until they     enter a valid input
    while(num >= 6 || num <= 1){
        cout<<"Enter a number from 1 to 6: ";
        cin >> num;
    }

    Answer = Square(num); // here I assign the return value of Square to Answer
    cout << "Squre( " << num << " ) = " << Answer << endl;  // check
    Answer = Triangle(num); // the same as above
    cout << "Triangle( " << num << " ) = " << Answer << endl;

    return 0;
}

int Square(int num){
    return (num * num); // store the result in return address
}

int Triangle(int num){
     return ( .5 * (num * num));
}

C ++的新手，我在调用我的函数时遇到了麻烦

1 个答案: