Question

编辑：我发布了a new question（而不是编辑），因为我尝试的内容和代码非常冗长，并且意味着完全取代了这个问题。

我正在使用PDO INSERT多行进入SQLite表，但是我在使用绑定参数执行查询时遇到了问题。我有三个模式表：

列schoolB_equivalencies：

equivalency_id INTEGER PRIMARY KEY AUTOINCREMENT
schoolA_id INTEGER NOT NULL
schoolB_id INTEGER NOT NULL
is_archived INTEGER NOT NULL
外键（schoolA_id）REFERENCES schoolA_courses（id）
外键（schoolB_id）参考schoolB_courses（id）

schoolA_courses的列：

schoolA_courses id INTEGER PRIMARY KEY AUTOINCREMENT
course_prefix TEXT
course_number INTEGER
......其他领域

schoolB_courses的列：

schoolB_courses id INTEGER PRIMARY KEY AUTOINCREMENT
course_prefix TEXT
course_number INTEGER
......其他领域

我正在尝试使用prepare()，值数组和子查询一次进行多次插入。一旦运行INSERT语句（插入一行）：

$dir = 'sqlite:/path/to/courses.sqlite3';
$dbh  = new PDO($dir) or die("error");

$stmt = $dbh->prepare('INSERT INTO schoolB_equivalencies (schoolA_id, schoolB_id, is_archived) VALUES ( (SELECT id from schoolA_courses WHERE course_number="103" AND course_prefix="RPED"), (SELECT id from schoolB_courses WHERE course_number="251" AND course_prefix="ARCH"),0)');

$stmt->execute();

但是，当我使用绑定参数和值数组合并相同的语句时，不会插入任何行：

$dir = 'sqlite:/path/to/courses.sqlite3';
$dbh  = new PDO($dir) or die("error");

$selections = array(
    0 => array(
        0 => "RPED", // THE schoolA COURSE PREFIX
        1 => "103", //THE schoolA COURSE NUMBER
        2 => "ARCH", //THE schoolB COURSE PREFIX
        3 => "251" //THE schoolB COURSE NUMBER
    ),
    1 => array(
        0 => "RPED", // THE schoolA COURSE PREFIX
        1 => "126", //THE schoolA COURSE NUMBER
        2 => "ARCH", //THE schoolB COURSE PREFIX
        3 => "261" //THE schoolB COURSE NUMBER
    )
);

$stmt = $dbh->prepare('INSERT INTO schoolB_equivalencies (schoolA_id, schoolB_id, is_archived) VALUES ( (SELECT id from schoolA_courses WHERE course_number=:schoolA_code AND course_prefix=:schoolA_prefix), (SELECT id from schoolB_courses WHERE course_number=:schoolB_code AND course_prefix=:schoolB_prefix),0)');

foreach ( $selections as $selection ):

    $stmt->bindParam(':schoolA_number', $selection[1]);
    $stmt->bindParam(':schoolA_prefix', $selection[0]);
    $stmt->bindParam(':schoolB_number', $selection[3]);
    $stmt->bindParam(':schoolB_prefix', $selection[2]);
    $stmt->execute();

    print_r($dbh->errorInfo());

endforeach;

error_info()的输出在两个插入上显示代码0000，这似乎是“成功”指示符，但没有插入任何行。基于单INSERT工作且error_info()报告成功的事实，我猜测我的绑定参数有什么问题。

Answer 1

首先......不应该是

$stmt->bindParam(':schoolA_number', $selection[0][1]);
$stmt->bindParam(':schoolA_prefix', $selection[0][0]);
$stmt->bindParam(':schoolB_number', $selection[0][3]);
$stmt->bindParam(':schoolB_prefix', $selection[0][2]);

OR

$stmt->bindParam(':schoolA_number', $selection[1][1]);
$stmt->bindParam(':schoolA_prefix', $selection[1][0]);
$stmt->bindParam(':schoolB_number', $selection[1][3]);
$stmt->bindParam(':schoolB_prefix', $selection[1][2]);

OR

foreach ( $selections as $selection ) {
   $stmt = $dbh->prepare('INSERT INTO schoolB_equivalencies (schoolA_id, schoolB_id, is_archived) VALUES ( (SELECT id from schoolA_courses WHERE course_number=:schoolA_code AND course_prefix=:schoolA_prefix), (SELECT id from schoolB_courses WHERE course_number=:schoolB_code AND course_prefix=:schoolB_prefix),0)');
   $stmt->bindParam(':schoolA_number', $selection[1]);
   $stmt->bindParam(':schoolA_prefix', $selection[0]);
   $stmt->bindParam(':schoolB_number', $selection[3]);
   $stmt->bindParam(':schoolB_prefix', $selection[2]);
   $stmt->execute();
   print_r($dbh->errorInfo());
}

AND NOT

foreach ( $selections as $selection ) {

   $stmt->bindParam(':schoolA_number', $selection[1]);
   $stmt->bindParam(':schoolA_prefix', $selection[0]);
   $stmt->bindParam(':schoolB_number', $selection[3]);
   $stmt->bindParam(':schoolB_prefix', $selection[2]);
   $stmt->execute();

   ...

}

具有子查询的

1 个答案: