Question

我正在研究我的JavaFx项目，我遇到了很多问题。我希望我的两个控制器能够相互通信。我已经阅读了几乎所有这个问题的解决方案，但我无法找到适合我的解决方案。我是初学程序员，我使用了一些现成的解决方案，我不完全理解，对于我的项目，我现在卡住了。我的工作是如此先进，我不能允许重做它。

这是我的代码：

let jsonData = try Data(contentsOf: URL(fileURLWithPath: filePath), options: .mappedIfSafe)

接口类

public class Main extends Application {
        public static final String ROOT = "Root";
        public static final String ROOT_FXML = "Root.fxml";
        public static final String FIRST_SCREEN = "FirstScreen";
        public static final String FIRST_SCREEN_FXML = "FirstScreen.fxml";
        public static final String SECOND_SCREEN = "SecondScreen";
        public static final String SECOND_SCREEN_FXML = "SecondScreen.fxml";

    @Override
public void start(Stage primaryStage) {
    this.primaryStage = primaryStage;
    ScreensController mainContainer = new ScreensController();
    initRootLayout();

    mainContainer.loadScreen(Main.FIRST_SCREEN, Main.FIRST_SCREEN_FXML);
    mainContainer.loadScreen(Main.SECOND_SCREEN, Main.SECOND_SCREEN_FXML);
    mainContainer.setScreen(Main.FIRST_SCREEN);


    Group root = new Group();
    root.getChildren().addAll(mainContainer);
    rootLayout.setCenter(root);
}

public void initRootLayout() {
    try {
        // Load root layout from fxml file.
        FXMLLoader loader = new FXMLLoader();
        loader.setLocation(Main.class.getResource("view/Root.fxml"));
        rootLayout = (BorderPane) loader.load();

        // Show the scene containing the root layout.
        Scene scene = new Scene(rootLayout);
        primaryStage.setScene(scene);
        primaryStage.show();
    } catch (IOException e) {
        e.printStackTrace();
    }
}

屏幕控制器类

public interface ControlledScreen {

    public void setScreenParent(ScreensController screenPage);
}

目前我有两个带有两个不同fxml文件的控制器类。它们看起来像这样：

public class ScreensController extends StackPane {

    private HashMap<String, Node> screens = new HashMap<>();

    public void addScreen(String name, Node screen) {
        screens.put(name, screen);
        System.out.println("added screen " + name);
    }

    public boolean loadScreen(String name, String resource) {
        try {
            FXMLLoader myLoader = new FXMLLoader(getClass().getResource(resource));
            Parent loadScreen = (Parent) myLoader.load();
            ControlledScreen myScreenControler = ((ControlledScreen) myLoader.getController());
            myScreenControler.setScreenParent(this);
            addScreen(name, loadScreen);
            return true;

        } catch (Exception e) {
            System.out.println(e.getMessage());
            return false;
        }
    }

    public boolean setScreen(final String name) {

        if (screens.get(name) != null) {
            if (!getChildren().isEmpty()) {
                getChildren().remove(0);
                // add new screen
                getChildren().add(0, screens.get(name));
            } else {
                getChildren().add(screens.get(name));
            }
            return true;
        } else {
            System.out.println("screen hasn't been loaded!\n");
            return false;
        }
    }

    public boolean unloadScreen(String name) {
        if (screens.remove(name) == null) {
            System.out.println("Screen didn't exist");
            return false;
        } else {
            return true;
        }
    }
}

第一屏和第二屏之间是否有简单的通讯方式？

堆栈窗口JavaFx之间的通信

0 个答案: