我从数据库中获取以下json数据:
[{"type":"Sig","value":"0.0"},{"type":"SH","value":"9.95"},{"type":"COD","value":"6.95"}][{"type":"Sig","value":"0.0"},{"type":"SH","value":"9.95"},{"type":"COD","value":"6.95"}][{"type":"Sig","value":"0.0"},{"type":"SH","value":"9.95"},{"type":"COD","value":"6.95"}][{"type":"Sig","value":"0.0"},{"type":"SH","value":"9.95"},{"type":"COD","value":"6.95"}]
我试图将所有value
值加在一起,所以:9.95 + 6.95 ......这样我就得到了67.6。
我尝试了以下代码,但我的重复值为16.9。
for ($i = 0; $i <= $count - 1 ; $i++) {
$charge = $service[$i]['charge'];
$serviceValue = json_decode($charge, true);
$totalservice = 0;
foreach ($serviceValue as $key => $value) {
$totalservice += $value['service_value'];
}
echo $totalservice;
}
答案 0 :(得分:1)
你可以这样做: -
onChildAdded
注意: - 每次循环进入下一次迭代时,在代码$jsonObj = json_decode($json); // Decode the JSON to OBJ
// Now loop and find the SUM
$total = 0;
foreach ($jsonObj as $item){
$total =+ $item->value;
}
// Print the SUM
echo "Sum : $total";
beome $totalservice
中,这就是为什么你得到相同值重复时间的原因。所以喜欢(@u_mulder所说的): -
0
答案 1 :(得分:1)
我做了以下更改。它工作正常。
$totalservice = 0;
for ($i = 0; $i <= $count-1 ; $i++) {
$charge = $service[$i]['charge'];
$serviceValue = json_decode($charge, true);
foreach ($serviceValue as $key => $value) {
$totalservice+= $value['service_value'];
}
echo $totalservice;
}
感谢您的帮助