Question

我正在尝试仅查找唯一ID号的频率。我尝试了PROC FREQ，但无法弄清楚如何做任何与SELECT DISTINCT等效的SAS。我运行了以下代码并获得了不加起来的数字。

代码： PROC SQL; SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n;

结果： 20599

代码：

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '1a (obs): Demonstrating knowledge of content and pedagogy';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '1a (p&p): Demonstrating knowledge of content and pedagogy';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '1e (obs): Designing coherent instruction';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '1e (p&p): Designing coherent instruction';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '2a: Creating an environment of respect and rapport';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '2d: Managing student behavior';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '3b: Using questioning and discussion techniques';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '3c: Engaging students in learning';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '3d: Using assessment in instruction';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '4e (obs): Growing and developing     professionally';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '4e (p&p): Growing and developing professionally';

在此处查看数据集的片段：https://docs.google.com/spreadsheets/d/1WDcsezb4xiT67J9t3Nlyi_QEofs0dhyZ23yC32ccbqg/edit?usp=sharing

结果： 1a（obs）：展示内容和教学方面的知识：700

1a（p＆amp; p）：展示内容和教学法知识：606

1e（obs）：设计连贯的指令：15622

1e（p＆amp; p）：设计连贯指令：1135

2a：创造尊重和融洽的环境：2466

2d：管理学生行为：1005

3b：使用提问和讨论技巧：808

3c：让学生参与学习：2516

3d：在教学中使用评估：3058

4e（obs）：专业成长和发展：5245

4e（p＆amp; p）：专业成长和发展：588

SUM = 33746

33746！= 20599

寻找有关出错的方法或是否有更好的方法来获得我想要的结果（MOTPCopmponentDescription的唯一MOTPID计数。非常感谢！

Answer 1

要讨论StackOverflow上的SAS问题，SASHELP库上的示例数据非常方便。让我们使用CARS数据集。;

标题＆＃34;您认为问题是没问题＆＃34;;

title2＆＃34;计算所有品牌＆＃34;;

proc sql;
    select count (distinct Make) as distinct_makes from sashelp.cars;
quit;

提供38 ;

title2＆＃34;计算生产具有一定数量汽缸的汽车的品牌＆＃34 ;;

proc sql;
    select 'n.a.' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = . union
    select ' 3  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 3 union
    select ' 4  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 4 union
    select ' 5  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 5 union
    select ' 6  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 6 union
    select ' 8  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 8 union
    select '10  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 10 union
    select '12  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 12;
quit;

给1个制作3个圆柱，26个产品4个圆柱等等，＆＃34;加起来＆＃34;超过80 ;

title2＆＃34;您可以手动验证这些列表中的结果＆＃34;;

proc sql;
    select Cylinders, Make, Model from sashelp.cars order by Cylinders, Make;
    select Make, Cylinders, Model from sashelp.cars order by Make, Cylinders;
quit;

title＆＃34;你所谓的解决方案正在产生不可预测的结果＆＃34 ;;

title2＆＃34;如果输入以单向排序＆＃34 ;;

，则会产生此结果

proc sort data=sashelp.cars out=cars_short2long;
    by length;
run;
proc sort data=cars_short2long nodupkey out=cars_short2long_clean dupout=dups;
    by Make;
run;
proc freq data=cars_short2long_clean;
    table Cylinders;
run;

表示没有人会制造10辆汽缸;

title2＆＃34;如果输入以另一种方式排序＆＃34 ;;

，它会产生此结果

proc sort data=sashelp.cars out=cars_long2short;
    by descending length;
run;
proc sort data=cars_long2short nodupkey out=cars_long2short_clean dupout=dups;
    by Make;
run;
proc freq data=cars_long2short_clean;
    table Cylinders;
run;

表示没有人会制作3辆汽车;

Answer 2

这是我制定的解决方案，它得到了我想要的确切结果：

data comment_analysis;
set WORK.'0__1_MOTP_COMMENTS_0001'n;
run;

proc sort data=comment_analysis nodupkey out=comment_analysis_clean dupout=dups;
by motpid;
run;

proc freq data=comment_analysis_clean;
table MOTPComponentDescription;
run;

这是我要找的输出： MOTPComponentDescription频率百分比

1a（obs）：展示内容和教学方面的知识520 2.52％

1a（p＆amp; p）：展示内容和教学方面的知识400 1.94％

1e（obs）：设计连贯指令11423 55.45％

1e（p＆amp; p）：设计相干指令526 2.55％

2a：创造尊重和融洽的环境1629 7.91％

2d：管理学生行为556 2.70％

3b：使用提问和讨论技巧563 2.73％

3c：让学生参与学习1593 7.73％

3d：在指令1818中使用评估8.83％

4e（obs）：专业成长和发展1235 6％

4e（p＆amp; p）：专业发展和发展336 1.64％

频率未加起来（SAS PROC SQL）

2 个答案: