Question

如何将元素分组到一行？我希望我的所有节点都在一行中，并在名字的孩子之后排序。我不知道我该怎么做！

＆GT; XML输入：

`<parent>
<Node  ID="a">
      <Name>first</Name>
      <ID>0x1</ID>
      <info>the first nod</info>
      <numb>8</numb>
      <Comment></Comment>
      <child>
      <Name>ch1</Name>
      <ID>0x11</ID>
      <info>the first child</info>
      <numb>7</numb>
      <Comment></Comment>
      </child>
      ...
      <other>
        <Name>attr</Name>
        <Value>No</Value>
        <DefaultUsed>No</DefaultUsed>
      </other>
      <other>
        <Name>attr</Name>
        <Value>No</Value>
        <DefaultUsed>No</DefaultUsed>
      </other>
</Node>
<Node  ID="b">
      <Name>second</Name>
      <ID>0x2</ID>
      <info>the second nod</info>
      <numb>9</numb>
      <Comment></Comment>
      <child>
      <Name>ch2</Name>
      <ID>0x22</ID>
      <info>the second child</info>
      <numb>7</numb>
      <Comment></Comment>
      </child>
      ....
      <other>
        <Name>attr1</Name>
        <Value>No</Value>
        <DefaultUsed>No</DefaultUsed>
      </other>
      <other>
        <Name>attr1</Name>
        <Value>No</Value>
        <DefaultUsed>No</DefaultUsed>
      </other>
</Node>
</parent>
`

XML输出

`<Node ; "Name= first","ID=0x1","info=the first nod","numb=8">
<child ;"Name= ch1","ID=0x11","info=the first child","numb=7">
....
<Node ; "Name= second","ID=0x2","info=the second nod","numb=9">
<child ;"Name= ch2","ID=0x22","info=the second child","numb=7">
`

有人能帮助我吗？非常感谢

Answer 1

您显示的输出不是格式良好的XML。您可以获得输出：

<?xml version="1.0" encoding="UTF-8"?>
<root>
   <Node Name="first" ID="0x1" info="the first nod" numb="8">
      <child Name="ch1" ID="0x11" info="the first child" numb="7"/>
   </Node>
   <Node Name="second" ID="0x2" info="the second nod" numb="9">
      <child Name="ch2" ID="0x22" info="the second child" numb="7"/>
   </Node>
</root>

将以下样式表应用于您的输入：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="/parent">
    <root>
        <xsl:apply-templates/>
    </root>
</xsl:template>

<xsl:template match="Node | child">
    <xsl:copy>
        <xsl:apply-templates select="*[not(*)]"/>       
        <xsl:apply-templates select="child"/>       
    </xsl:copy>
</xsl:template>

<xsl:template match="*[text()]">
    <xsl:attribute name="{name()}">
        <xsl:value-of select="." />
    </xsl:attribute>
</xsl:template>

</xsl:stylesheet>

加了：

要按child对Name元素进行排序，请更改：

<xsl:apply-templates select="child"/>

为：

<xsl:apply-templates select="child">  
    <xsl:sort select="Name" data-type="text" order="ascending"/>
</xsl:apply-templates>

使用Xsl在单行上对xml节点进行分组

1 个答案:

加了：