Question

我已经在这里尝试过关于它的每个问题，但我的代码仍然会返回400，因为我尝试做的每一个请求都没有得到我做错的事。

HttpURLConnection connection = null;

InputStream in = null;

try {

    URL url = new URL(uri);

    connection = (HttpURLConnection) url.openConnection();

    connection.setReadTimeout(10000);
    connection.setConnectTimeout(20000);
    connection.setRequestMethod("POST");

    connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded");

    connection.setDoInput(true);
    connection.setDoOutput(true);

    String query = "";

    if (Validator.isNotNull(paramsMap) && !paramsMap.isEmpty()) {

        Uri.Builder builder = new Uri.Builder();

        for (Map.Entry<String, String> entry : paramsMap.entrySet()) {

            builder.appendQueryParameter(entry.getKey(), entry.getValue());
        }

        query = builder.build().getEncodedQuery();
    }

    if (!query.isEmpty()) {

        OutputStream os = connection.getOutputStream();

        BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));

        writer.write(query);
        writer.flush();
        writer.close();

        os.close();

    }

    connection.connect();

    int status = connection.getResponseCode();

    if (status == 200) {

        in = connection.getInputStream();
    } else {
        in = connection.getErrorStream();
    }

} finally {

    connection.disconnect();
}

return in;

Answer 1

我会尝试使用一个单独的工具让它工作（有很多浏览器插件可以让你创建POST请求（Postman，HttpRequester等）使用其中一个确切地知道你需要POST到什么让它工作。一旦你在其中一个工具中工作，你就可以在Java代码中做同样的事情。

HttpURLConnection POST返回400 Bad Request

1 个答案: