我有一个嵌套的json对象，我需要删除空值并创建新的json，它应该只包含数据对象。 json文件：
myData = [{
"id": 1,
"values": [{
"value": ""
}]
}, {
"id": 2,
"values": [{
"value": 213
}]
}, {
"id": 3,
"values": [{
"value": ""
}, {
"value": ""
}, {
"value": "abc"
}]
},{
"id": 4,
"values": [{
"value": ""
}]
},{
"id": 33,
"values": [{
"value": "d"
}]
}];
输出应为：
myNewData = [{
"id": 2,
"values": [{
"value": 213
}]
}, {
"id": 3,
"values": [{
"value": "abc"
}]
},{
"id": 33,
"values": [{
"value": "d"
}]
}];
到目前为止，我创造了这个：
angular.module('myapp',[])
.controller('test',function($scope){
$scope.myData = [{
"id": 1,
"values": [{
"value": ""
}]
}, {
"id": 2,
"values": [{
"value": 213
}]
}, {
"id": 3,
"values": [{
"value": ""
}, {
"value": ""
}, {
"value": "abc"
}]
},{
"id": 4,
"values": [{
"value": ""
}]
},{
"id": 33,
"values": [{
"value": "d"
}]
}];
})
.filter('filterData',function(){
return function(data) {
var dataToBePushed = [];
data.forEach(function(resultData){
if(resultData.values && resultData.values != "")
dataToBePushed.push(resultData);
});
return dataToBePushed;
}
});
HTML：
<div ng-app="myapp">
<div ng-controller="test">
<div ng-repeat="data in myData | filterData">
Id:{{ data.id }}
</br>
Values: {{ data.values }}
</div>
</div>
</div>
我无法访问和删除值对象内的值。现在我只是使用ng-repeat显示数据，但我需要为此创建一个新的json文件。
答案 0 :(得分：2)
您使用AngularJS控制器中的数组执行Array.prototype.map()和Array.prototype.filter()。映射执行过滤器的所有对象以排除具有空值item.values.value的项，而不是过滤器以获取具有值的值的数组元素：
var myData = [{"id": 1,"values": [{ "value": ""}]}, {"id": 2,"values": [{"value": 213}]}, {"id": 3,"values": [{"value": ""}, {"value": ""}, {"value": "abc"}]}, {"id": 4,"values": [{"value": ""}]}, {"id": 33,"values": [{"value": "d"}]}],
myDataFiltered = myData
.map(function (item) {
item.values = item.values.filter(function (itemValue) {
return itemValue.value;
});
return item;
})
.filter(function (item) {
return item.values.length;
});
console.log(myDataFiltered);.as-console-wrapper { max-height: 100% !important; top: 0; }
ES6：
myDataFiltered = myData
.map(item => {
item.values = item.values.filter(itemValue => itemValue.value);
return item;
})
.filter(item => item.values.length);
答案 1 :(得分：0)
您可以使用多个for循环。
myData = [{
"id": 1,
"values": [{
"value": ""
}]
}, {
"id": 2,
"values": [{
"value": 213
}]
}, {
"id": 3,
"values": [{
"value": ""
}, {
"value": ""
}, {
"value": "abc"
}]
},{
"id": 4,
"values": [{
"value": ""
}]
},{
"id": 33,
"values": [{
"value": "d"
}]
}];
function clone(obj){ return JSON.parse(JSON.stringify(obj));}
var result = [];
for(var i = 0; i < myData.length; i++){
var current = clone(myData[i]);
for(var j = 0; j < current.values.length; j++){
if(current.values[j].value == null || current.values[j].value == ""){
current.values.splice(j, 1);
j--;
}
}
if(current.values.length > 0) result.push(current);
}
console.log(myData);
console.log(result);
答案 2 :(得分：0)
如果要完全删除它们，可以像这样迭代数组;
angular.forEach($scope.myData, function(data){
for(var i=0; i < data.values.length; i++){
if(data.values[i] !== ""){
break;
}
delete data;
}
});
if语句检查数组中的所有值，如果它不等于＆＃34;＆＃34;则中断，否则如果所有值都是=＆＃34;＆＃34;它删除了对象。
希望它有所帮助！
答案 3 :(得分：0)
试试这个：
var myData = [{"id": 1,"values": [{ "value": ""}]}, {"id": 2,"values": [{"value": 213}]}, {"id": 3,"values": [{"value": ""}, {"value": ""}, {"value": "abc"}]}, {"id": 4,"values": [{"value": ""}]}, {"id": 33,"values": [{"value": "d"}]}]
let result=[],p=[];
myData.filter(el => {
p=[];
el.values.filter(k => {k.value != '' ? p.push({value : k.value}) : null});
if(p.length) result.push({id : el.id, values : p})
})
console.log('result', result);
答案 4 :(得分：0)
这是一个完成这项工作的递归函数。
仅当myData是数组并且其中的值或其子项是对象的集合时，这才有效。
var myData = [{"id": 1, "values": [{"value": ""}] }, {"id": 2, "values": [{"value": 213 }] }, {"id": 3, "values": [{"value": ""}, {"value": ""}, {"value": "abc"}] },{"id": 4, "values": [{"value": ""}] },{"id": 6, "values": ""},{"id": 33, "values": [{"value": "d"}] }];
function removeEmptyValues (arr) {
var res = false;
/* Iterate the array */
for (var i = 0; i < arr.length; i++) {
/* Get the object reference in the array */
var obj = arr[i];
/* Iterate the object based on its key */
for (var key in obj) {
/* Ensure the object has the key or in the prototype chain */
if (obj.hasOwnProperty(key)) {
/* So, the object has the key. And we want to check if the object property has a value or not */
if (!obj[key]) {
/*
If it has no value (null, undefined, or empty string) in the property, then remove the whole object,
And reduce `i` by 1, to do the re-checking
*/
arr.splice(i--, 1);
/* Amd set whether the removal occurance by setting it to res (result), which we will use for the next recursive function */
res = true;
/* And get out from the loop */
break;
}
/* So, the object has a value. Let's check whether it's an array or not */
if (Array.isArray(obj[key])) {
/* Kay.. it's an array. Let's see if it has anything in it */
if (!obj[key].length) {
/* There's nothing in it !! Remove the whole object again */
arr.splice(i--, 1);
/* Amd set whether the removal occurance by setting it to res (result), which we will use for the next recursive function */
res = true;
/* Yes.. gets out of the loop */
break;
}
/*
Now this is where `res` is being used.
If there's something removed, we want to re-do the checking of the whole object
*/
if ( removeEmptyValues(obj[key]) ) {
/* Something has been removed, re-do the checking */
i--;
}
}
}
}
}
return res;
}
removeEmptyValues (myData);
答案 5 :(得分：0)
你会采取正确的方式，但需要更多这样的操作：
try-catchcontext.evaluatePolicy(policy, localizedReason: ...) { (success: Bool, error: Error?) in
DispatchQueue.main.async {
if success {
...
} else if let error = error as? LAError {
switch error.code {
case LAError.authenticationFailed:
...
}
}
}
}