美好的一天。我试图阅读txt
文件。所以这是txt
SS,SS,SS,BSM160801870,1
SS,SS,SS,BSM160801825,1
SS,SS,SS,BSM160801812,1
SS,SS,SS,BSM160701676,1
SS,SS,SS,BSM160501311,1
SS,SS,SS,BSM160501351,1
SS,SS,SS,BSM160701721,1
SS,SS,SS,BSM160501269,1
所以我用这个
读取文件$myfile = fopen($file, "r") or die("Unable to open file!");
$textfile = fread($myfile,filesize($file));
echo $textfile;
但结果是这样的
SS,SS,SS,BSM160801870,1 SS,SS,SS,BSM160801825,1 SS,SS,SS,BSM160801812,1 SS,SS,SS,BSM160701676,1 SS,SS,SS,BSM160501311,1 SS,SS,SS,BSM160501351,1 SS,SS,SS,BSM160701721,1 SS,SS,SS,BSM160501269,1
所以我想在结果的每个;
中给space
,所以我尝试使用这个
$myfile = fopen($file, "r") or die("Unable to open file!");
$textfile = fread($myfile,filesize($file));
$textfiles = str_replace(" ",";",$textfile);
echo $textfiles;
但没有帮助。
我想要的结果是这样的
SS,SS,SS,BSM160801870,1;SS,SS,SS,BSM160801825,1;SS,SS,SS,BSM160801812,1;SS,SS,SS,BSM160701676,1;SS,SS,SS,BSM160501311,1;SS,SS,SS,BSM160501351,1;SS,SS,SS,BSM160701721,1;SS,SS,SS,BSM160501269,1
我怎样才能实现这一目标?提前谢谢。
如果我这样做,工作正常
$string = "SS,SS,SS,BSM160801870,1 SS,SS,SS,BSM160801825,1 SS,SS,SS,BSM160801812,1 SS,SS,SS,BSM160701676";
$textfiles = str_replace(" ",";",$string);
echo $textfiles;
答案 0 :(得分:1)
在回显文件内容时,所有新行都将转换为简单空格。
您需要将\r\n
替换为;
preg_replace('/\r\n/', ';', file_get_contents($myfile))