Question

如果我们有一个文本文件如下：

６   &   ロク３ &   サン
９   &   キュウ
０   &   ゼロ５ &   ゴ
７   &   ナナみぎ    &   ミギひだり   &   ヒダリ
うえ  &   ウエ

如何将其读入python以获取每个“列”的列表，如下所示：

a = ["6", "9", "0", "7", "うえ"]
b = ["ロク３" , "キュウ", "ゼロ５", "ナナみぎ", "ウエ"]
c = ["サン", "", "ゴ}", "ミギひだり", ""]
d = ["", "ヒダリ", "", "", ""]

Answer 1

试试这个：

with open(path, 'r') as inputFile:
    lines = list()

    for line in inputFile:
        lines.append(line.split("&"))

    maxLen = len(max(lines, key=lambda x: len(x)))

    for line in lines:
        while len(line) < maxLen:
            line.append(" ")

    column0 = [line[0] for line in lines]
    column1 = [line[1] for line in lines]
    .
    .
    .

此外，如果您想删除“单元格”中的空格，请使用replace方法：

without_spaces = with_spaces.replace(" ", "")

要使用它，只需替换

lines.append(line.split("&"))

与

lines.append(line.replace(" ", "").split("&"))

Answer 2

itertools.izip_longest对任务来说非常方便。

import itertools

def cleanup(alist):
    return [item.strip() for item in alist]

with open('input.txt', 'r') as input_file:
    lines = input_file.readlines()
    contents = [cleanup(line.split('&')) for line in lines]
    zipped = itertools.izip_longest(*contents, fillvalue='')

    for column in zipped:
        print column

请注意，zipped实际上是所有列的迭代器。

逐行将文本文件读入多个列表

2 个答案: