它是互联网上关于Red-Black BST Java实现的算法。我对这个程序中名为val
的变量感到困惑。这是代码:
package tools;
public class redBlack2 {
private static final boolean RED = true;
private static final boolean BLACK = false;
private Node root;
public redBlack2() {}
private class Node {
private int key;
private int val;
private Node left, right;
private boolean color;
public Node(int key, int val, boolean color) {
this.key = key;
this.val = val;
this.color = color;
}
}
private boolean isRed(Node x) {
if (x == null) return false;
return x.color == RED;
}
public int get(int key) {
return get(root, key);
}
private int get(Node x, int key) {
while (x != null) {
if (key < x.key) x = x.left;
else if (key > x.key) x = x.right;
else return x.val;
}
System.out.println("There is no such key.");
return 0;
}
public boolean contains(int key) {
return get(key) != 0;
}
public void put(int key, int val) {
root = put(root, key, val);
root.color = BLACK;
}
private Node put(Node h, int key, int val) {
if (h == null) return new Node(key, val, RED);
if (key<h.key) h.left = put(h.left, key, val);
else if (key>h.key) h.right = put(h.right, key, val);
else if (key == h.key) h.val = val;
if (isRed(h.right) && !isRed(h.left)) h = rotateLeft(h);
if (isRed(h.left) && isRed(h.left.left)) h = rotateRight(h);
if (isRed(h.left) && isRed(h.right)) flipColors(h);
return h;
}
private Node rotateRight(Node h) {
Node x = h.left;
h.left = x.right;
x.right = h;
x.color = x.right.color;
x.right.color = RED;
return x;
}
private Node rotateLeft(Node h) {
Node x = h.right;
h.right = x.left;
x.left = h;
x.color = x.left.color;
x.left.color = RED;
return x;
}
private void flipColors(Node h) {
h.color = !h.color;
h.left.color = !h.left.color;
h.right.color = !h.right.color;
}
public static void main(String[] args) {
redBlack2 r = new redBlack2();
r.put(34,1);
r.put(23,2);
r.put(65,3);
r.put(73, 4);
System.out.print(r.get(73));
}
}
这只是我们给树内数字的标记吗?那么我们还没有钥匙作为标记吗?为什么我们仍然需要变量val
?
答案 0 :(得分:1)
是的,你是对的,它就像一个标记。我们确实可以用一个变量实现这个算法,即key
。在这个算法中,val
被存储为一种我们需要跟踪的数据类型。
例如考虑这个
你有几个编号的盒子,如34,23,65,73,你想要 对它们实施RB Tree操作。所以这些数字放在盒子上 类似于算法中的
key
。现在考虑每个盒子里面都包含许多球。这些球 可以看作存储在盒子里面的数据,你需要 跟踪它。因此,这可以被视为
val
。
您甚至可以更进一步,通过将val
的数据类型更改为List
或Map
甚至用户 - 来跟踪框内的一些内容定义的对象。它仍然会以同样的方式工作。
答案 1 :(得分:0)
在此实现中,此数据结构的行为类似于val
,这意味着它将键映射到值。 value
是$ sudo service mysql start
Job for mysql.service failed. See 'systemctl status mysql.service' and 'journalctl -xn' for details.
$ sudo cat /var/log/messages
...
Jan 13 04:19:25 localhost mysqld_safe: 2017-01-12T19:19:25.588436Z mysqld_safe Skipping wsrep-recover for empty datadir: /var/lib/mysql
Jan 13 04:19:25 localhost mysqld_safe: 2017-01-12T19:19:25.590385Z mysqld_safe Assigning 00000000-0000-0000-0000-000000000000:-1 to wsrep_start_position
Jan 13 04:19:27 localhost mysql-systemd: State transfer in progress, setting sleep higher
Jan 13 04:19:40 localhost mysqld_safe: 2017-01-12T19:19:40.723030Z mysqld_safe mysqld from pid file /var/run/mysqld/mysqld.pid ended
Jan 13 04:19:47 localhost mysql-systemd: /usr/bin/mysql-systemd: 137 行: kill: (19791) - そのようなプロセスはありません
Jan 13 04:19:47 localhost mysql-systemd: ERROR! mysqld_safe with PID 19791 has already exited: FAILURE
Jan 13 04:19:47 localhost systemd: mysql.service: control process exited, code=exited status=1
Jan 13 04:19:47 localhost mysql-systemd: WARNING: mysql pid file /var/run/mysqld/mysqld.pid empty or not readable
Jan 13 04:19:47 localhost mysql-systemd: ERROR! mysql already dead
Jan 13 04:19:47 localhost systemd: mysql.service: control process exited, code=exited status=2
...
的常见缩写,这是非常自我解释的。它可以是Java中存在的任何类型,无论是原始的还是引用的。