如何检查数组中是否存在数组键?
我需要检查数组中是否存在用户ID,我找到了下面的数组,
Array
(
[0] => Array
(
[user_id] => 1482309797
[week] => 1
[type] => 1
[commission] => 4000
)
[1] => Array
(
[user_id] => 1482309797
[week] => 1
[type] => 1
[commission] => 0
)
[2] => Array
(
[user_id] => 1482309797
[week] => 1
[type] => 1
[commission] => 4000
)
[3] => Array
(
[user_id] => 1482309797
[week] => 1
[type] => 1
[commission] => 0
)
[4] => Array
(
[user_id] => 1483096072
[week] => 1
[type] => 1
[commission] => 4000
)
[5] => Array
(
[user_id] => 1483333245
[week] => 1
[type] => 1
[commission] => 2000
)
)
我想检查用户ID是否存在,我试过下面的代码
foreach ($com_array as $report) {
$user_id=$report['user_id'];
if(array_key_exists($user_id,$output_array)){
echo "Eid found";
}else{
echo "id not found";
}
}
任何人请帮助。
答案 0 :(得分:1)
试试这个......
foreach ($com_array as $key=>$value) {
if(array_key_exists("user_id",$value)){
echo "id found";
}else{
echo "id not found";
}
}
答案 1 :(得分:1)
foreach ($com_array as $report) {
if(isset($report['user_id'])){
echo "Eid found";
}else{
echo "id not found";
}
}
尝试上面的代码,您将获得输出。
答案 2 :(得分:0)
多维数组没有内置函数。你可以做一个像:
function findKey($array, $keySearch)
{
foreach ($array as $key => $item) {
if ($key == $keySearch) {
echo 'yes, it exists';
return true;
}
else {
if (is_array($item) && findKey($item, $keySearch)) {
return true;
}
}
}
return false;
}
答案 3 :(得分:0)
如果您只是检查是否存在密钥,则可以执行此操作。
$user_id_arr = array_column($output_array, 'user_id'); // Get your user_id to a single dimension array
foreach ($com_array as $report) {
if ( in_array($report['user_id'], $user_id_arr) ){
echo "ID Found";
} else {
echo "ID Not Found";
}
}
谢谢!