Question

def comparing_numbers(number1,number2,number3,number4,number5, numbers(), correct_numbers):
    if number1 == numbers():
        correct_numbers = correct_numbers + 1
print("")
if number2 == numbers():
    correct_numbers = correct_numbers + 1
print("")
if number3 == numbers():
    correct_numbers = correct_numbers + 1
print("")
if number4 == numbers():
    correct_numbers = correct_numbers + 1
print("")
if number5 == numbers():
    correct_numbers = correct_numbers + 1

comparing_numbers(number1,number2,number3,number4,number5, numbers(), correct_numbers)

print(correct_numbers)

所以基本上我需要一些代码，让我的五个变量（number1，number2，number3，number4，number5）搜索一个名为（numbers（））的数组，如果变量中的数字与任何数字匹配在数组中，它将一个加到我的变量（correct_numbers）。我需要它搜索五次（每个变量）

我试图制作一些代码来解释我所说的内容，但它无法正常工作

由于

Answer 1

以下代码应该完成工作。

如果它出现在给定的列表（数组）中，它会检查数字中的每个数字，并返回找到的数字。

def findSimilars(n1, n2, n3, n4, n5, all):

    correct_found = 0

    # all is a list of numbers to check if the numbers are in

    my_numbers = [n1,n2,n3,n4,n5] # make the numbers a list for simple iteration

    for n in my_numbers: # go over each of the numbers
        if n in all: # if the current number is in my_numbers
            correct_found += 1

    return correct_found


all_numbers = [0,1,2] # ... All the values you want to check if your numbers are there
correct_times_found = findSimilars(1,2,3,4,5,all_numbers) # An example for function call
print "Number of times found: %d" % (correct_times_found)

Answer 2

您可以将您的号码存储为列表吗？如果是这样的话：

numbersToCheck = [number1,number2,number3,number4,number5]
numbers = [1,2,3,4,5]

correct_numbers = len([num for num in numbers if num in numbersToCheck])

Answer 3

您正在复制函数中的代码，该代码可能属于for循环。了解我们如何简化功能，并迭代您的数字列表：

def comparing_numbers(check_numbers, numbers(), correct_numbers):
    for number in check_numbers:
        if number in numbers():
            correct_numbers += 1
    return correct_numbers

check_numbers = [number1, number2, number3, number4, number5]
correct_numbers = 0
print(comparing_numbers(check_numbers, numbers(), correct_numbers)

Answer 4

可能这就是你要做的事情

def comparing_numbers(number1,number2,number3,number4,number5, numbers):
  correct_numbers = 0
  for number in [number1,number2,number3,number4,number5]:
    if number in numbers:
      correct_numbers += 1  
  return correct_numbers

correct_numbers = comparing_numbers(number1,number2,number3,number4,number5, numbers)

print(correct_numbers)

Answer 5

in语句会检查您的号码中是否包含该号码。如果是，则将其添加到correct_numbers。

if number1 in numbers:
    correct_numbers += 1
if number2 in numbers:
    correct_numbers += 1
if number3 in numbers:
    correct_numbers += 1
if number4 in numbers:
    correct_numbers += 1
if number5 in numbers:
    correct_numbers += 1

如何获取变量来搜索数组，并检查数字是否匹配

5 个答案: