PHP - Sqlite在CSV中搜索关键字 - 仅显示第一个结果

Question

我正在尝试实现一个功能，用户可以将“关键字”添加到csv文件中，然后PHP代码将遍历关键字以使用“LIKE”函数查找匹配项。

$row2 = 1;
if (($handle = fopen("test.csv", "r")) !== FALSE) {
    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
        $num = count($data);
        echo "<p> $num fields in line $row2: <br /></p>\n";
        $row2++;

        echo "<table id='example1' class='table table-bordered table-hover dataTable' role='grid'>";
        echo "<tr>";
        echo "<th aria-controls='example1' aria-sort='ascending'> FilePath </th>";
        echo "<th> HashValue </th>";
        echo "<th> NameNoPath </th>";
        echo "<th> FileExtension </th>";
        echo "</tr>";
        for ($c = 0; $c < $num; $c++) {
            echo "1";
            echo "Data is:" . $data[$c] . '<br><br>';
            //$data[$c] = $tst;
            $sql = "SELECT * FROM `hash` WHERE `HashValue` LIKE '$data[$c]' ";
            echo $sql;
            $result = mysqli_query($conn, $sql);
            if ($result) {
                while ($row2 = mysqli_fetch_assoc($result)) {
                    echo "TEST";
                    echo "<tr>";
                    echo "<td>" . $row2['Filename'] . '<br>';
                    echo "<td>" . $row2['HashValue'] . '<br>';
                    echo "<td>" . $row2['NameNoPath'] . '<br>';
                    echo "<td>" . $row2['FileExtension'] . '<br>';
                    echo "</tr>";
                }
                echo "</table>";
                echo "2";
            }
                //echo $data[$c] . "<br />\n";
        }
    }
fclose($handle);
}

该代码适用于仅匹配的FIRST记录 我已将问题缩小到while ($row2 = mysqli_fetch_assoc($result))循环。所有测试“回声”都完美地工作到那一点 为什么while循环没有正确执行？