Question

所需的陈述是：

SELECT `id` FROM `user` WHERE `email`='aaa@aaa.com'

...返回单个单元格作为结果。

我的PDO准备好的声明不会返回任何内容。我错过了什么？

$email = "aaa@aaa.com";

$statement = $db->prepare("SELECT `id` FROM `user` WHERE `email`=':email;'");
$statement->execute(['email' => $email]);               
$user = $statement->fetch();
echo $user;

Answer 1

报价不应该用于：电子邮件

$statement = $db->prepare("SELECT `id` FROM `user` WHERE `email`=:email");

如@siyual所说

Answer 2

试试这个：

$email = "aaa@aaa.com";

$stmt = $db->prepare("SELECT `id` FROM `user` WHERE `email`=:email");
$stmt->bindParam(':email', $email, PDO::PARAM_STR);
$stmt->execute();
$row = $stmt->fetchAll(PDO::FETCH_ASSOC);
if (!empty($row)) {
    print_r($row);
}else{
    echo 'no result :/';
}

Answer 3

像这样使用它：

$statement = $db->prepare("SELECT `id` FROM `user` WHERE `email`=:email;"); 

$statement->execute(['email' => $email]);

另外，请确保

$db->prepare('select 1');

返回有效的查询结果。

为什么我的SQL语句没有返回结果？

3 个答案: