Question

我刚刚开始使用Python并编写了一个简单的“Rock，Paper，Scissors”游戏，但它对玩家和ai选择的比较方式对我来说没有意义。他们的赢/输条件似乎与我设定的相反。

#Rock Paper Scissors
import random

print("Welcome to Rock, Paper, Scissors!")
print()
print()
choices = ["rock", "paper", "scissors"]

choices[0] < choices[1]
choices[1] < choices[2]
choices[2] < choices[0]

def game():
    player_choice = input("What will you choose?:  "  ).lower()
    print()
    ai_choice = random.choice(choices)
    who_chose = print("You chose",player_choice,"and the computer chose",ai_choice)

    if player_choice not in choices:
        print("Sorry, that is not a valid option, please choose again.")
        print()
        game()
    elif player_choice > ai_choice:
        who_chose
        print("The computer wins!")
        print()
    elif player_choice == ai_choice:
        who_chose
        print("It was a tie!")
        print()
    else:
        who_chose
        print("You Win!")
        print()
    play_again = input("Do you want to play again? (y/n): ").lower()
    if play_again in ["yes", "y"]:
        game() 
    else:
        print("Thanks for playing") 


game()

我在这里设置了他们的层次结构：

choices[0] < choices[1]
choices[1] < choices[2]
choices[2] < choices[0]

但是当我比较它们时，它似乎在这里落后，但它的作用与岩石剪刀的规则相符：

elif player_choice > ai_choice:
        who_chose
        print("The computer wins!")
        print()

Answer 1

choices[0] < choices[1]
choices[1] < choices[2]
choices[2] < choices[0]

＆LT;是一个布尔运算符，意味着它尝试比较值并确定它是真还是假，它不是赋值。尝试在控制台中输入其中一个语句。 Python按字母顺序解释字符串的层次结构。

现在我能想到的最简单的方法就是创建一个真值表。

#rock, paper, scissors
t=[0, 1, 0; #rock
   0, 0, 1; #paper
   1, 0, 0] #scissors

索引如下：

t[player_choice,ai_choice]

如果它返回1，那么你就赢了。

为什么这些布尔值在Python中工作？

1 个答案: