我有一个树形控件,其复选框使用http://www.sephiroth.it/file_detail.php?id=151#
中的控件当我更改dataProvider(即通过单击复选框)时,我无法让控件更新,我可以让它更新的唯一方法是使用滚动条。如何强制更新?我已经尝试过所有可能的方法了吗? (见下面的更新)
另外如何重置树(拼写所有节点,滚动到大树的顶部)?
package offerta.monkeywrench.components
{
import offerta.monkeywrench.components.componentClasses.TreeCheckBoxItemRenderer;
import mx.collections.ArrayCollection;
import mx.events.TreeEvent;
public class WatchTree extends TreeCheckBox
{
public var idProperty:String;
public var watchFactory:Function;
private var _wSet:Boolean = false;
/* clientId: */
private var _clientId:String;
[Bindable]
public function get clientId():String
{
return _clientId;
}
public function set clientId(value:String):void
{
this._clientId = value;
}
/* //clientId */
/* watching: */
private var _watching:ArrayCollection;
[Bindable]
public function set watching(value:ArrayCollection):void
{
this._watching = value;
}
public function get watching():ArrayCollection
{
return this._watching;
}
/* //watching */
override public function initialize() :void
{
super.initialize();
addEventListener("itemCheck", onItemCheck, false, 0, true);
}
private function isWatching(id:String):Boolean
{
for each(var w:Object in this._watching)
{
if(w[this.idProperty]==id) return true;
}
return false;
}
private function onItemCheck(event:TreeEvent):void
{
var item:Object = event.item as Object;
var currentValue:uint = (event.itemRenderer as TreeCheckBoxItemRenderer).checkBox.checkState;
if(item.children==null)
{
currentValue==2 ? addWatch(item.Id) : removeWatch(item.Id);
}
else
{
for each(var x:Object in item.children)
{
currentValue==2 ? addWatch(x.Id) : removeWatch(x.Id);
}
}
updateParents(item, currentValue);
updateChilds(item, currentValue);
this.dataProvider.refresh();
super.invalidateProperties();
super.invalidateDisplayList();
super.updateDisplayList(this.unscaledWidth, this.unscaledHeight);
}
private function updateParents(item:Object, value:uint):void
{
var checkValue:String = (value == ( 1 << 1 | 2 << 1 ) ? "2" : value == ( 1 << 1 ) ? "1" : "0");
var parentNode:Object = item.parent;
if(parentNode)
{
for each(var x:Object in parentNode.children)
{
if(x.checked != checkValue)
{
checkValue = "2"
}
}
parentNode.checked = checkValue;
updateParents(parentNode, value);
}
}
private function updateChilds(item:Object, value:uint):void
{
var middle:Boolean = (value&2<<1)==(2<<1);
if(item.children!=null && item.children.length>0&&!middle)
{
for each(var x:Object in item.children)
{
x.checked = value == (1<<1|2<<1) ? "2" : value==(1<<1) ? "1" : "0";
updateChilds(x, value);
}
}
}
private function addWatch(id:String):void
{
if(isWatching(id)) return;
this._watching.addItem(this.watchFactory(id, this.clientId));
}
private function removeWatch(id:String):void
{
for(var i:int=0, n:int=this._watching.length; i<n; ++i)
{
if(this._watching[i][this.idProperty]==id)
{
this._watching.removeItemAt(i);
return;
}
}
}
public function update(__watching:ArrayCollection, __clientId:String):void
{
clientId = __clientId;
watching = __watching;
if(this.dataProvider!=null)
{
var ws:ArrayCollection = ArrayCollection(this.dataProvider);
for each(var group:Object in ws)
{
var count:int = 0;
for each(var child:Object in group.children)
{
if(isWatching(child.Id))
{
child.checked = "1";
count++;
}
}
group.checked = (count==0 ? "0" : (count==group.children.length ? "1" : "2"));
}
this._wSet = false;
var dp:ArrayCollection = ArrayCollection(this.dataProvider);
dp.refresh();
super.invalidateProperties();
super.invalidateDisplayList();
super.updateDisplayList(this.unscaledWidth, this.unscaledHeight);
//scroll up the list???
//collapse? (doesn't work)
this.expandItem(null, false);
}
}
}
}
答案 0 :(得分:20)
我发现Tree控件在Flex中有点敏感。我最终强制重绘的方法是断开dataProvider并重新连接,然后强制验证,有点像这样:
private function forceRedraw(tree:Tree, dataProvider:Object):void
{
var scrollPosition:Number = tree.verticalScrollPosition;
var openItems:Object = tree.openItems;
tree.dataProvider = dataProvider;
tree.openItems = openItems;
tree.validateNow();
tree.verticalScrollPosition = scrollPosition;
}
我想这偶然会回答你问题的第二部分,因为你所要做的就是将openItems集合归零并将verticalScrollPosition设置为0.
答案 1 :(得分:1)
您可能还有另一个问题:无论何时检查项目,树都会滚动到顶部,这很烦人。要解决此问题,您应该以这种方式更新TreeCheckBox.as文件: 在函数checkHandler中: private function checkHandler(event:TreeEvent):void;
评论commitProperties();调用
现在它应该运作良好。
干杯。
答案 2 :(得分:0)
这个解决方案我遇到了一些小问题,var scrollPosition:Number = tree.verticalScrollPosition;经常是0 ??