Question

我们目前正在尝试从Android手机请求GPS权限，以便我们可以在Google地图上显示当前位置。我们在清单标记下包含了应用程序标记之外的清单：

    <uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>

以下是我们的代码无效的部分，它无法识别MY_PERMISSIONS_REQUEST_ACCESS_FINE_LOCATION：

 if (ActivityCompat.checkSelfPermission(this,
            android.Manifest.permission.ACCESS_FINE_LOCATION)
            != PackageManager.PERMISSION_GRANTED) {
        // Should we show an explanation?
        if (ActivityCompat.shouldShowRequestPermissionRationale(this,
                android.Manifest.permission.ACCESS_FINE_LOCATION)) {
            // Show an explanation to the user *asynchronously* -- don't block
            // this thread waiting for the user's response! After the user
            // sees the explanation, try again to request the permission.
        } else {
            // No explanation needed, we can request the permission.
            ActivityCompat.requestPermissions(this,
                    new String[]{Manifest.permission.ACCESS_FINE_LOCATION}, MY_PERMISSIONS_REQUEST_ACCESS_FINE_LOCATION);
            // MY_PERMISSIONS_REQUEST_READ_CONTACTS is an
            // app-defined int constant. The callback method gets the
            // result of the request.
        }
    }

我们还包括“import android.Manifest”。

提前致谢！

Answer 1

您必须将其定义为：

public static int MY_PERMISSIONS_REQUEST_ACCESS_FINE_LOCATION =1;

然后将结果记为：

    @Override
public void onRequestPermissionsResult(int requestCode,
        String permissions[], int[] grantResults) {
    switch (requestCode) {
        case MY_PERMISSIONS_REQUEST_ACCESS_FINE_LOCATION : {
            // If request is cancelled, the result arrays are empty.
            if (grantResults.length > 0
                && grantResults[0] == PackageManager.PERMISSION_GRANTED) {

                // permission was granted, yay! Do the
                // contacts-related task you need to do.

            } else {

                // permission denied, boo! Disable the
                // functionality that depends on this permission.
            }
            return;
        }

        // other 'case' lines to check for other
        // permissions this app might request
    }
}

在代码中无法识别MY_PERMISSIONS_REQUEST_ACCESS_FINE_LOCATION权限

1 个答案: