电子邮件将发送给不符合if
中设置条件的最后一个人。
我无法理解为什么它不会将电子邮件发送给符合条件的文件中的其他人。
import smtplib, openpyxl, sys from email.mime.multipart
import MIMEMultipart from email.mime.text
import MIMEText from email.mime.base
import MIMEBase from email
import encoders
wb = openpyxl.load_workbook('Book1.xlsx')
sheet = wb.get_sheet_by_name('Sheet1')
lastCol = sheet.max_column
latestMonth = sheet.cell(row=1, column=lastCol).value
unpaidMembers = {}
for r in range(2, sheet.max_row + 1):
payment = sheet.cell(row=r, column=lastCol).value
if payment != 'Y':
name = sheet.cell(row=r, column=1).value
email = sheet.cell(row=r, column=2).value
unpaidMembers[name] = email
fromaddr = "xxx@xxxx.com"
msg = MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = email
msg['Subject'] = "Hi"
body = "Hello, This is a test message. Please check attachment"
msg.attach(MIMEText(body, 'plain'))
filename = "xxxxx.pdf"
attachment = open("\\\xxxx.pdf","rb")
part = MIMEBase('application', 'octet-stream')
part.set_payload((attachment).read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; filename= %s" % filename)
msg.attach(part)
smtp0bj = smtplib.SMTP('smtp-mail.outlook.com', 587)
smtp0bj.ehlo()
smtp0bj.starttls()
smtp0bj.login(fromaddr, 'xxxx')
text = msg.as_string()
smtp0bj.sendmail(fromaddr, email, text)
smtp0bj.quit()
答案 0 :(得分:0)
email
设置为for循环中的最后一个值,这就是为什么它只是将电子邮件发送给最后一个人。
您应该做的是创建收件人列表,然后使用该信息:
...
...
recipients = []
unpaidMembers = {}
for r in range(2, sheet.max_row + 1):
payment = sheet.cell(row=r, column=lastCol).value
if payment != 'Y':
name = sheet.cell(row=r, column=1).value
email = sheet.cell(row=r, column=2).value
unpaidMembers[name] = email
recipients.append(email)
...
...
msg["To"] = ", ".join(recipients)
...
...
smtp0bj.sendmail(fromaddr, recipients, text)
按照此SO帖子中的答案获取更多详细信息:How to send email to multiple recipients using python smtplib?