Question

输入字符串 -

select CONVERT(VARCHAR(14), 
               CONVERT(DECIMAL(14, 0), RAND() * POWER(CAST(10 as BIGINT), 14))
              )

输出字符串 -

'0|33|6|2|30|12|4|1|8|29|9|34|7|13|11|5|3|31|10|36|37|37|37|38|39|40|44|65|66'

在SQL Server 2008中需要这个。

我已将值拆分为|然后将值插入临时表，然后连接值。有没有更好的评估？

Answer 1

没有解析/拆分功能

Declare @String varchar(max) = '0|33|6|2|30|12|4|1|8|29|9|34|7|13|11|5|3|31|10|36|37|37|37|38|39|40|44|65|66'

Select Sorted = Stuff((Select '|' +RetVal 
                       From (
                              Select RetSeq = Row_Number() over (Order By (Select null))
                                    ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                                From  (Select x = Cast('<x>'+ replace((Select @String as [*] For XML Path('')),'|','</x><x>')+'</x>' as xml).query('.')) as A 
                                Cross Apply x.nodes('x') AS B(i)
                            ) A
                       Order By cast(RetVal as int) 
                       For XML Path ('')),1,1,'')

使用Parse / Split功能

Declare @String varchar(max) = '0|33|6|2|30|12|4|1|8|29|9|34|7|13|11|5|3|31|10|36|37|37|37|38|39|40|44|65|66'

Select Sorted = Stuff((Select '|' +RetVal 
                       From [dbo].[udf-Str-Parse-8K](@String,'|') 
                       Order By cast(RetVal as int) 
                       For XML Path ('')),1,1,'')

返回

0|1|2|3|4|5|6|7|8|9|10|11|12|13|29|30|31|33|34|36|37|37|37|38|39|40|44|65|66

UDF（如果需要）

CREATE FUNCTION [dbo].[udf-Str-Parse-8K] (@String varchar(max),@Delimiter varchar(25))
Returns Table 
As
Return (  
    with   cte1(N)   As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
           cte2(N)   As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 a,cte1 b,cte1 c,cte1 d) A ),
           cte3(N)   As (Select 1 Union All Select t.N+DataLength(@Delimiter) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter)) = @Delimiter),
           cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter,@String,s.N),0)-S.N,8000) From cte3 S)

    Select RetSeq = Row_Number() over (Order By A.N)
          ,RetVal = LTrim(RTrim(Substring(@String, A.N, A.L)))
    From   cte4 A
);
--Orginal Source http://www.sqlservercentral.com/articles/Tally+Table/72993/
--Much faster than str-Parse, but limited to 8K
--Select * from [dbo].[udf-Str-Parse-8K]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse-8K]('John||Cappelletti||was||here','||')

Answer 2

declare @str varchar(100) =
    '0|33|6|2|30|12|4|1|8|29|9|34|7|13|11|5|3|31|10|36|37|37|37|38|39|40|44|65|66';

declare @s varchar(100) = '|' + @str + '|';
declare @result varchar(100);    

with D(d) as 
(
    select v from (values (0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) V(v)     
),
N(n) as 
(
    select top (len(@s) - 1) 
        row_number() over (order by (select 1)) from D d1, D d2
),
S(s) as
(       
    select substring(@s, n + 1, charindex('|', @s, n + 1) - (n + 1)) 
    from N where substring(@s, n, 1) = '|'
)
select top (100) @result = isnull(@result + '|', '') + s 
from S order by cast(s as int);

print @result;

如何在SQL Server中的字符串中对数值进行排序

2 个答案: