在10个LED显示屏上显示健康栏

Question

对于编程课程，我必须用fubarino和10 led显示屏制作一个小游戏。在游戏中的某一点上，我需要显示玩家的健康栏或积分。健康状况可以在10到0之间。我使用了这段代码。

  value = -1;
//set 1 bit off per point lost
  for(int i = 10; i>points[playerNr]; i--){
    value &= !(1<<(points[playerNr]-1));
  }
  showValue(value);

方法showValue（int value）不是问题，已经可以用于其他用途。它显示了当时led栏上整数为1的位。

我的问题是，这段代码翻转了所有的LED。所以我认为它将值设置为0。

我将在下面添加其余方法。但我不认为问题就在那里。

// playerNr is either 0 or 1 for one player or 2 for both
void showPoints(int playerNr){
  bool both = false;
  //subtract one point from both players if playerNr == 2
  if(playerNr == 2){
    both = true;
    playerNr = 1;
  }
  points[playerNr]--;
  value = -1;
  //flash all lights to show that the points are going to be shown
  showValue(value);
  delay(50);
  //set 1 bit off per point lost
  for(int i = 10; i>points[playerNr]; i--){
    value &= !(1<<(points[playerNr]-1));
  }
  showValue(value);
  //game position is either 0 or 9
  pos = 9*playerNr;
  //ascend is true if playerNr is 0 and vice versa
  ascend = !playerNr;
  if(both){
    pointLost = 0;
  } else {
    pointLost = -1;
  }
  //reset the game if points are 0
  if(points[playerNr]==0){
    points[0] = 10;
    points[1] = 10;
    points[playerNr]++;
    pointLost = playerNr;
  }
  timer = 1000;
}