$("#home").on("pageload", function() {
console.log("test2");
var url = window.location.search;
var split = url.split('=');
var vendorID = split[1];
$.ajax({
type: "POST",
url: "vendorpull.php",
data: 'id=' + vendorID,
cache: false,
success: function(data)
{
document.getElementById('vendor-data').innerHTML = data;
}
});
});
除非页面在物理上刷新,否则此代码似乎不会被触发。我已尝试过网页显示,pagebeforeshow和其他内容,但它并没有改变。测试console.log甚至没有触发。加载vendor.html?id = 1后,应立即触发此事件,即导航到包含上述AJAX代码的页面。有什么建议吗?
答案 0 :(得分:0)
$("#home").ready(function() { //You can also use $(document).ready(function() {
console.log("test2");
var url = window.location.search;
var split = url.split('=');
var vendorID = split[1];
$.ajax({
type: "POST",
url: "vendorpull.php",
data: 'id=' + vendorID,
cache: false,
success: function(data)
{
document.getElementById('vendor-data').innerHTML = data;
}
});
});
答案 1 :(得分:0)
这个jQuery Mobile 1.4.5代码将为每次访问页面重新加载数据:
$(document).on("pagecontainerbeforeshow", function(e, ui) {
var pageId = $(":mobile-pagecontainer").pagecontainer("getActivePage").prop("id");
/* JQM NAVIGATE #2 */
if (typeof ui.toPage == "object") {
/* manipulate page navigating to */
switch (pageId) {
case "home":
var url = window.location.search;
var split = url.split('=');
var vendorID = split[1];
$.ajax({
type: "POST",
url: "vendorpull.php",
data: 'id=' + vendorID,
beforeSend: function() {
$.mobile.loading("show");
},
cache: false,
success: function(data) {
$("#vendor-data").html(data);
$("#home .ui-content").trigger("updatelayout");
},
complete: function() {
$.mobile.loading("hide");
},
error: function() {
$.mobile.loading("hide");
}
});
break;
default:;
}
}
});