Question

我是xml解析的新手，无法决定如何在java中解析这个复杂的xml文件。我能够解析简单的xml文件，但是当涉及到复杂的xml文件时，我很困惑。无法使用java读取xml的元素。这是我的示例xml文件。

<?xml version="1.0"?>
<env:ContentEnvelope xsi:schemaLocation="http://fundamental.schemas.financial.jso.com/Fundamental/2011-07-07/ 
https://theshare.jso.com/sites/TRM-IA/Content%20Marketplace/Strategic%20Data%20Interfaces/SDI%20Schemas/Schemas/Fundamentals/2015-09-25/FundamentalMaster.xsd"
    xmlns:esg="http://fundamental.schemas.financial.jso.com/ESGSupportingInfo/2011-07-07/"
    xmlns:md="http://data.schemas.financial.jso.com/metadata/2010-10-10/"
    xmlns:cr="http://fundamental.schemas.financial.jso.com/CoraxData/2012-10-25/"
    xmlns:ful="http://fundamental.schemas.financial.jso.com/FundamentalLineItem/2011-07-07/"
    xmlns:fun="http://fundamental.schemas.financial.jso.com/Fundamental/2011-07-07/"
    xmlns:ir="http://fundamental.schemas.financial.jso.com/FinancialInstrumentRelationship/2011-07-07/"
    xmlns:fl="http://fundamental.schemas.financial.jso.com/FinancialLineItem/2011-07-07/"
    xmlns:pe="http://fundamental.schemas.financial.jso.com/FinancialPeriod/2011-07-07/"
    xmlns:seg="http://fundamental.schemas.financial.jso.com/FinancialSegment/2011-07-07/"
    xmlns:sr="http://fundamental.schemas.financial.jso.com/FinancialSource/2011-07-07/"
    xmlns:sli="http://fundamental.schemas.financial.jso.com/StandardizedLineItem/2011-07-07/"
    xmlns:ss="http://fundamental.schemas.financial.jso.com/StandardizedStatement/2011-07-07/"
    xmlns:fs="http://fundamental.schemas.financial.jso.com/FinancialStatement/2011-07-07/"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:env="http://data.schemas.tfn.jso.com/Envelope/2008-05-01/" minVers="1.0" majVers="3" pubStyle="Message">
    <env:Header>
        <env:Info>
            <env:Id>urn:uuid:069527ab-2c10-48bb-b3d2-206f4e66e5d2</env:Id>
            <env:TimeStamp>2016-12-23T10:09:09+00:00</env:TimeStamp>
        </env:Info>
        <fun:OrgId>20240</fun:OrgId>
        <fun:PartitionId>1</fun:PartitionId>
    </env:Header>
    <env:Body minVers="0.0" majVers="1" contentSet="Fundamental">
        <env:ContentItem action="Insert">
            <env:Data xsi:type="fun:FundamentalDataItem">
                <fun:Fundamental effectiveTo="9999-12-31T00:00:00+00:00" effectiveFrom="2013-06-29T00:55:15.313+00:00" uniqueFuamentalSet="0054341342">
                    <fun:OrganizationId objectType="Organization" objectTypeId="404510">42565596</fun:OrganizationId>
                    <fun:PrimaryReportingEntityCode>A4C67</fun:PrimaryReportingEntityCode>
                    <fun:TotalPrimaryReportingShares>567923000.00000</fun:TotalPrimaryReportingShares>
                    <fun:LocalLanguageId>505074</fun:LocalLanguageId>
                    <fun:IndustryGroups>
                        <fun:IndustryGroup validTo="9999-12-31T00:00:00+00:00" validFrom="1900-01-01T00:00:00+00:00">
                            <fun:GroupCode>BNK</fun:GroupCode>
                            <fun:GroupName languageId="505074">Bank</fun:GroupName>
                            <fun:TaxonomyId>1</fun:TaxonomyId>
                            <fun:IndustryGroupCodeId>3011649</fun:IndustryGroupCodeId>
                        </fun:IndustryGroup>
                    </fun:IndustryGroups>
                    <fun:GaapCode>CAG</fun:GaapCode>
                    <fun:ConsolidationBasis>Consolidated</fun:ConsolidationBasis>
                    <fun:IsFiling>true</fun:IsFiling>
                    <fun:ConsolidationBasisId>3013598</fun:ConsolidationBasisId>
                    <fun:GaapCodeId>3011536</fun:GaapCodeId>
                    <fun:Taxonomies>
                        <fun:Taxonomy>1</fun:Taxonomy>
                    </fun:Taxonomies>
                    <fun:WorldScopeIds>
                        <fun:WorldScopeId validTo="9999-12-31T00:00:00+00:00" validFrom="2012-03-31T00:00:00+00:00">C12436390</fun:WorldScopeId>
                    </fun:WorldScopeIds>
                </fun:Fundamental>
            </env:Data>
        </env:ContentItem>

Answer 1

JAXB绝对会帮到你。由于你正在处理复杂的xml文件，我建议采用下面的方法（我同意它是冗长的和手动的，但应该可以正常工作）。

1）从给定的xml内容生成xsd模式

2）在eclipse中创建一个JAXB项目并创建并清空XSD文件并使用上面生成的xsd模式编写它

3）将.xsd文件转换为pojo右键单击.xsd文件并生成JAXB类

4）现在编写一个代码来解组数据并运行它，这应该会给你一个相应的java类。

如何在JAVA中解析复杂的嵌套xml文件

1 个答案: