Question

我有两个选择。

一个用于Leagues，另一个用于Divisions

我想创建一个Pipe来过滤Divisions，具体取决于所选的League。

提供以下数据。如果我选择Random Beer League仅TwoFour，则SixPack应显示为Divisions选择的选项。

leagues = [
  {id: 1, leagueName: 'Recreation League' },
  {id: 2, leagueName: 'Random Beer League' } 
];

divisions = [
  {id: 1, divisionName: 'SoGreen', leagueId: 1, leagueName: 'Recreation League' },
  {id: 2, divisionName: 'Yellow', leagueId: 1, leagueName: 'Recreation League' },
  {id: 3, divisionName: 'TwoFour', leagueId: 2, leagueName: 'Random Beer League' },
  {id: 4, divisionName: 'SixPack', leagueId: 2, leagueName: 'Random Beer League' }
];

PLUNKER to show the setup

*注意 - plunker中的数据是硬编码的，但在我的应用程序中设置了Observable。

Answer 1

我创建了一个自定义管道并用它来过滤部门下拉列表。

@Pipe({
    name: 'myfilter',
    pure: false
})

export class MyFilterPipe implements PipeTransform {
    transform(items: any[], args: any[]): any {
        return items.filter(item => item.leagueName.indexOf(args.leagueName) > -1);
    }
}


<option *ngFor="let division of divisions | myfilter:leagueSelected" [ngValue]="division">{{division.divisionName}}</option>

请查看此Plnkr

如何编写Angular ngFor管道来按对象属性过滤对象数组？

1 个答案: