这是我的第一个使用ui-grid
和AngularJS
nodejs
框架作为后端的express
应用程序。
API运行良好,数据正在流传,但我对事件的顺序以及对Angular上下文的异步$http.get()
调用的使用感到困惑。
所以,我需要在屏幕上放置网格。此网格需要从API加载数据。这是html页面上的网格对象:
<div class="tile-body" ng-controller="AdminUsersGridCtrl">
<div id="grid" ui-grid="gridOptions" class="grid"></div>
</div>
这是我的控制器:
app.controller('AdminUsersGridCtrl', function ($scope, $http, uiGridConstants) {
$http.get('/api/admin/user')
.then(function (response) {
$scope.myData = response;
$scope.gridOptions = {
data: 'myData',
enableFiltering: true,
columnDefs: [
{ field: 'firstName' },
{ field: 'lastName' },
{ field: 'jobTitle'},
{
field: 'email',
filter: {
condition: uiGridConstants.filter.ENDS_WITH,
placeholder: 'ends with'
}
},
{
field: 'phone',
filter: {
condition: function(searchTerm, cellValue) {
var strippedValue = (cellValue + '').replace(/[^\d]/g, '');
return strippedValue.indexOf(searchTerm) >= 0;
}
}
},
]
};
},
function (error) {
console.log(error);
});
});
我在这个序列中遇到错误:
TypeError: Cannot read property 'data' of undefined
at new <anonymous> (ui-grid.js:3130)
at Object.invoke (angular.js:4604)
at extend.instance (angular.js:9855)
at nodeLinkFn (angular.js:8927)
at angular.js:9231
at processQueue (angular.js:15552)
at angular.js:15568
at Scope.$eval (angular.js:16820)
at Scope.$digest (angular.js:16636)
at Scope.$apply (angular.js:16928)
我不知道这里发生了什么。该错误消息来自哪里?
答案 0 :(得分:3)
您应该在promise调用之外初始化gridOptions。
app.controller('AdminUsersGridCtrl', function ($scope, $http, uiGridConstants) {
$scope.gridOptions = {
enableFiltering: true,
columnDefs: [
{ field: 'firstName' },
{ field: 'lastName' },
{ field: 'jobTitle'},
{
field: 'email',
filter: {
condition: uiGridConstants.filter.ENDS_WITH,
placeholder: 'ends with'
}
},
{
field: 'phone',
filter: {
condition: function(searchTerm, cellValue) {
var strippedValue = (cellValue + '').replace(/[^\d]/g, '');
return strippedValue.indexOf(searchTerm) >= 0;
}
}
},
]
};
$http.get('/api/admin/user')
.then(function (response) {
$scope.gridOptions.data = response.data; // Content is in the response.data
},
function (error) {
console.log(error);
});
});