Question

好吧所以我必须制作一个随机的tictactoe检查器，显示x胜出，o胜，以及何时出现平局。所以我遇到的问题是它不会显示关系，有时会说x或o赢了，否则就赢了。我不知道在我的代码中要改变什么，因为在我进行对角线检查之前，它会打印出关系。这是整个代码，但我很确定问题是来自检查板部分，使xWin和oWin出现真实我无法找到它在那做什么。

package test;

import java.util.Scanner;
import java.util.Random;

public class TicTacToe {
    public static void main(String[] args) {
        System.out.println("Welcome to random Tic Tac Toe Checker. Let's see our randomly generated board.");
        int dimension = 3;
        char[][] board = new char[dimension][dimension];
        Random r = new Random();

        for (int i = 0; i < 3; i++) // filling board
        {
            for (int j = 0; j < 3; j++) {
                int choice = r.nextInt(2);
                if (choice == 0) {
                    board[i][j] = 'X';
                } else if (choice == 1) {
                    board[i][j] = 'O';
                }
            }
        }
        for (int i = 0; i < 3; i++) // filling board
        {
            for (int j = 0; j < 3; j++) {
                System.out.print(board[i][j]);
            }
            System.out.println();
        }

        boolean xWin = false;// checking board, order horizontal,vertical,left
                                // and right diagonal
        boolean oWin = false;

        for (int i = 0; i < 3; i++) {
            boolean lineWin = true;
            for (int j = 0; j < 3; j++) {
                if (board[i][j] != board[i][0]) {
                    lineWin = false;

                }
            }
            if (lineWin == true) {
                if (board[i][0] == 'X') {
                    xWin = false;
                }
                if (board[i][0] == 'O') {
                    oWin = false;
                }

            }
        }
        for (int j = 0; j < 3; j++) {
            boolean lineWin = true;
            for (int i = 0; i < 3; i++) {
                if (board[i][j] != board[0][j]) {
                    lineWin = true;

                }
            }
            if (lineWin == true) {
                if (board[0][j] == 'X') {
                    xWin = true;
                }
                if (board[0][j] == 'O') {
                    oWin = true;
                }

            }
        }
        boolean lineWin = true;
        for (int i = 0; i < 3; i++) {
            if (board[0][0] != board[i][i]) {
                lineWin = false;
            }
            if (lineWin == true) {
                if (board[0][0] == 'X') {
                    xWin = true;
                }
                if (board[0][0] == 'O') {
                    oWin = true;
                }

            }
        }
        lineWin = true;
        for (int i = 0; i < 3; i++) {
            if (board[0][0] != board[i][2 - i]) {
                lineWin = false;
            }
            if (lineWin == true) {
                if (board[0][0] == 'X') {
                    xWin = true;
                }
                if (board[0][0] == 'O') {
                    oWin = true;
                }
            }
        }

        if (xWin == false && oWin == false)// printing winners
        {
            System.out.println("CAT!It's a tie no one wins");
        }
        if (xWin == true) {
            System.out.println("X wins!");
        }

        if (oWin == true) {
            System.out.println("O wins!");
        }

    }
}

Answer 1

我修正了布尔错误以及对角线逻辑：

import java.util.Random;

public class TicTacToe {
  private static final int DIMENSION = 3;

  public static void main(String[] args) {
    System.out.println("Welcome to random Tic Tac Toe Checker. Let's see our randomly generated board.");
    char[][] board = new char[DIMENSION][DIMENSION];
    final Random r = new Random();

    for (int i = 0; i < DIMENSION; i++) {
      for (int j = 0; j < DIMENSION; j++) {
        int choice = r.nextInt(2);
        if (choice == 0) {
          board[i][j] = 'X';
        } else if (choice == 1) {
          board[i][j] = 'O';
        }
      }
    }
    for (int i = 0; i < DIMENSION; i++) {
      for (int j = 0; j < DIMENSION; j++) {
        System.out.print(board[i][j]);
      }
      System.out.println();
    }


    boolean xWin = false;
    boolean oWin = false;

    for (int i = 0; i < DIMENSION; i++) {
      boolean lineWin = true;
      for (int j = 0; j < DIMENSION; j++) {
        if (board[i][j] != board[i][0]) {
          lineWin = false;
        }
      }
      if (lineWin) {
        if (board[i][0] == 'X') {
          xWin = true;
        }
        if (board[i][0] == 'O') {
          oWin = true;
        }

      }
    }
    for (int j = 0; j < DIMENSION; j++) {
      boolean lineWin = true;
      for (int i = 0; i < DIMENSION; i++) {
        if (board[i][j] != board[0][j]) {
          lineWin = false;
        }
      }
      if (lineWin) {
        if (board[0][j] == 'X') {
          xWin = true;
        }
        if (board[0][j] == 'O') {
          oWin = true;
        }

      }
    }
    boolean lineWin = true;
    for (int i = 0; i < DIMENSION; i++) {
      if (board[0][0] != board[i][i]) {
        lineWin = false;
      }
    }
    if (lineWin) {//this check should not be in the loop
      if (board[0][0] == 'X') {
        xWin = true;
      }
      if (board[0][0] == 'O') {
        oWin = true;
      }

    }
    lineWin = true;
    for (int i = 0; i < DIMENSION; i++) {
      if (board[DIMENSION - 1][0] != board[i][DIMENSION - 1 - i]) {
        lineWin = false;
      }
    }
    if (lineWin) {//this check should not be in the loop
      if (board[DIMENSION - 1][0] == 'X') {
        xWin = true;
      }
      if (board[DIMENSION - 1][0] == 'O') {
        oWin = true;
      }
    }
    if (xWin == true && oWin == true) {//printing winners
      System.out.println("Both players won!");
    }
    if (xWin == false && oWin == false) {
      System.out.println("CAT!It's a tie no one wins");
    }
    if (xWin == true) {
      System.out.println("X wins!");
    }

    if (oWin == true) {
      System.out.println("O wins!");
    }
  }
}

注意：您可以增加DIMENSION以获得笑声。

Answer 2

在第一个区块

if(lineWin == true)
{
  if(board[i][0] == 'X')
  {
    xWin = false;
  }
  if(board[i][0] == 'O')
  {
    oWin = false;
  }
}

应更改如下。

if(lineWin == true)
{
  if(board[i][0] == 'X')
  {
    xWin = true;
  }
  if(board[i][0] == 'O')
  {
    oWin = true;
  }
}

此外，在第二个块中，部分

if(board[i][j] != board[0][j])
{
  lineWin = true;
}

应更改如下。

if(board[i][j] != board[0][j])
{
  lineWin = false;
}

Answer 3

我认为此文件中的主要问题出现在中间位置，特别是第34-66行，您可以对相同字符的水平和垂直行进行初始检查。

for (int i = 0; i < 3; i++) {
        boolean lineWin = true;
        for (int j = 0; j < 3; j++) {
            if (board[i][j] != board[i][0]) {
                lineWin = false;

            }
        }
        if (lineWin == true) {
            if (board[i][0] == 'X') {
                xWin = false; //THESE LINES SHOULD BE CHANGING THE WIN CONDITION TO TRUE
            }
            if (board[i][0] == 'O') {
                oWin = false; //LISTED ABOVE
            }

        }
    }
    for (int j = 0; j < 3; j++) {
        boolean lineWin = true;
        for (int i = 0; i < 3; i++) {
            if (board[i][j] != board[0][j]) {
                lineWin = true; //THIS LINE SHOULD BE FALSE

            }
        }
        if (lineWin == true) {
            if (board[0][j] == 'X') {
                xWin = true;
            }
            if (board[0][j] == 'O') {
                oWin = true;
            }
        }

我列出了一些修改代码并使其按照您希望的方式运行的更改。看起来在错误的时间将布尔值声明为true或false时会出现一些错误，因此应该可以解决问题。

随机Tic Tac Toe检查器问题

3 个答案: