无法将VALUE_STRING解码为base64

时间:2017-01-11 17:51:06

标签: java jackson

我正在尝试使用fastxml jackson反序列化json,Json中的一个字段是一个字符串但我需要在字节数组中读取相同的PFB Bean和主类

public class Serialization implements Serializable{

    private static final long serialVersionUID = 5894318390213780082L;
    private String name = null;

    @JsonDeserialize(using = StringtoByteArray.class)
    private byte[] pass = null;
//getter setter
}  

public class StringtoByteArray extends JsonDeserializer<byte []> {

    @Override
    public byte[] deserialize(JsonParser jsonParser, DeserializationContext deserializationContext)
            throws IOException, JsonProcessingException {
        return (jsonParser.getBinaryValue());
    }
}

public class App 
{
    public static void main(String[] args) throws JsonGenerationException, JsonMappingException, IOException {
        Serialization sr = new Serialization();
        ObjectMapper mapper = new ObjectMapper();

        sr = mapper.readValue(new File("D:\\check.json"), Serialization.class);
        System.out.println("sr values ::" +sr.toString());

        mapper.writeValue(new File("c:\\user.json"), sr);
    }
}

我的json

{
      "name": "AD",
      "pass": "pp"
}

在反序列化获取时 线程“main”中的异常com.fasterxml.jackson.databind.JsonMappingException:无法将VALUE_STRING解码为base64(MIME-NO-LINEFEEDS):base64内容中的非法字符“”(代码0x22) 请建议

1 个答案:

答案 0 :(得分:1)

如果使用Java 8:在我的Deserialize实现中,我需要返回

return (Base64.getEncoder().encode(jsonParser.getText().getBytes()))
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