Question

我设法制作了一个导航抽屉并试图让按钮立即工作。

代码：

public class FourthFragment extends Fragment {

    @Override
    public View onCreateView(LayoutInflater inflater,
                             ViewGroup container,
                             Bundle savedInstanceState) {
        return inflater.inflate(R.layout.fourth_layout, container, false);
    }
    public void buttona1(View view){
        Intent browserIntent = new Intent(Intent.ACTION_VIEW,
                                          Uri.parse("https://www.google.nl"));
        startActivity(browserIntent);
    }
}

布局：

<Button
    android:text="Magister"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:onClick="buttona1"
    android:id="@+id/button2"
    android:visibility="visible"
    android:layout_alignParentLeft="true"
    android:layout_alignParentStart="true"
    android:layout_alignParentTop="true"
    android:layout_alignParentRight="true"
    android:layout_alignParentEnd="true" />

问题在于，当我在手机中打开应用程序并转到按钮页面时，按下按钮，应用程序将关闭并停止工作。

Answer 1

您应初始化Context中的fragment contsructor，MainActivity会在初始化freagment时通过context.startActivity(YOUR_INTENT);传递，并致电DECLARE q_id_from_update varchar2(45); q_id_to_update varchar2(45); BEGIN SELECT QUESTION_ID INTO q_id_to_update FROM QUESTION WHERE QUESTION.NAME = 'QUESTION_A'; SELECT QUESTION_ID INTO q_id_from_update FROM QUESTION WHERE QUESTION.NAME = 'QUESTION_B'; FOR a IN (SELECT ANSWER.QUESTION_ID, ANSWER.USER_ID, ANSWER.ANSWER FROM ANSWER WHERE ANSWER.QUESTION_ID = q_id_from_update AND ANSWER.ANSWER IS NOT NULL) LOOP UPDATE ANSWER SET ANSWER.ANSWER = a.ANSWER WHERE ANSWER.USER_ID = a.USER_ID AND ANSWER.QUESTION_ID = q_id_to_update; END LOOP; COMMIT; END; / 希望这会对你有所帮助

Answer 2

您的代码似乎正确，但您需要在活动中创建方法buttona1 和片段两者。你不能从xml中调用该方法驻留在Fragment中，而不是在Activity

中

您可以在onCreateView方法

中使用以下代码

    View v=inflater.inflate(R.layout.fourth_layout, container, false);
    Button myButton=(Button)v.findViewById(R.id.button2);
    myButton.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View view) {
    buttona1(view)
    });
return v;

也替换此行

 startActivity(browserIntent);

带

getActivity().startActivity(browserIntent);

按钮链接到互联网使应用程序崩溃

2 个答案: