所以我使用python来创建基于文本的口袋妖怪游戏。然而，一个错误不断涌现，敌人在一个回合中进行两次攻击，每次都是相同的，即使它们应该是随机的。 布局道歉
CODE
import math, random
print("-------------POKEMON BROWN-------------")
print("welcome to pokemon brown")
print("choose a pokemon")
print("Charmander, Squirtle, Bulbasaur")
pokemon_1 = input()
pokemon_1 = (pokemon_1.lower())
print("ahh " + pokemon_1 + " a good choice")
enemy = 1
print("Ok lets battle!")
battle = 1
hp = 20
mp = 10
enemyhp = 20
enemymp = 10
print("----Battle Start----")
print("")
battle = 1
while True:
turn = 1
player_turn = 1
if(pokemon_1 == "squirtle"):
player_turn = 1
print("----Your turn----")
print("")
print("Pokemon:" + pokemon_1 + "/HP = " + str(hp) + "/MP = " + str(mp))
print("Tackle(1 DMG), Tail Whip(2 DMG, 2MP), Water Gun(5 DMG, 10 MP), Back")
move = input()
move = (move.lower())
if(move == "tackle"):
print("Your Squirtle uses tackle and deals 1 DMG")
enemyhp -= 1
turn = 1
if(move == "tail whip"):
if(mp >= 2):
print("Your Squirtle uses tail whip and deals 2 DMG")
enemyhp -= 2
mp -= 2
turn = 1
else:
print("not enough MP")
if (move == "water gun"):
if(mp >= 10):
print("Your Squirtle uses water gun and deals 5 DMG")
enemyhp -= 5
mp -= 10
turn = 1
else:
print("not enough MP")
if(pokemon_1 == "charmander"):
player_turn = 1
print("")
print("----Your turn----")
print("Pokemon: " + pokemon_1 + "/HP = " + str(hp) + "/MP = " + str(mp))
print("Scratch(2 DMG), Ember(4 DMG, 5MP), Back")
move = input()
move = (move.lower())
if(move == "scratch"):
print("Your Charmander uses scratch and deals 2 DMG")
enemyhp -= 2
turn = 1
if(move == "ember"):
if(mp >= 2):
print("Your Charmander uses Ember and deals 4 DMG")
enemyhp -= 4
mp -= 5
turn = 1
else:
print("not enough MP")
if(pokemon_1 == "bulbasaur"):
player_turn = 1
print("")
print("----Your turn----")
print("Pokemon: " + pokemon_1 + "/HP = " + str(hp) + "/MP = " + str(mp))
print("Tackle(1 DMG), Vine whip(5 DMG, 5MP)")
move = input()
move = (move.lower())
if(move == "scratch"):
print("Your Bulbasuar uses Tackle and deals 2 DMG")
enemyhp -= 2
turn = 1
if(move == "tail whip"):
if(mp >= 2):
print("Your Bulbasaur uses Vine Whip and deals 5 DMG")
enemyhp -= 4
mp -= 5
turn = 1
else:
print("not enough MP")
if(turn == 1):
if(enemy == 1):
print("")
print("----Enemy's turn----")
print("Enemy Pokemon: Squirtle / HP = " + str(enemyhp) + " / MP = " + str(enemymp))
if(enemymp == 10):
enemy_move = random.randint(1,6)
if(enemymp < 10 and enemymp >= 2):
enemy_move = random.randint(1,5)
if(enemymp < 2):
enemy_move = 0
if(enemy_move == 1 or 2 or 3):
print("Enemy Squirtle uses tackle and deals 1 DMG")
hp -= 1
turn = 0
if(enemy_move == 4 or 5):
if(mp >= 2):
print("Enemy Squirtle uses tail whip and deals 2 DMG")
hp -= 2
enemymp -= 2
turn = 0
else:
print("not enough MP")
if (enemy_move == 6):
if(mp >= 10):
print("Enemy Squirtle uses water gun and deals 5 DMG")
hp -= 5
enemymp -= 10
turn = 0
else:
print("not enough MP")
SHELL
-------------POKEMON BROWN-------------
welcome to pokemon brown
choose a pokemon
Charmander, Squirtle, Bulbasaur
charmander
ahh charmander a good choice
Ok lets battle!
----Battle Start----
----Your turn----
Pokemon: charmander/HP = 20/MP = 10
Scratch(2 DMG), Ember(4 DMG, 5MP), Back
scratch
Your Charmander uses scratch and deals 2 DMG
----Enemy's turn----
Enemy Pokemon: Squirtle / HP = 18 / MP = 10
Enemy Squirtle uses tackle and deals 1 DMG
Enemy Squirtle uses tail whip and deals 2 DMG
----Your turn----
Pokemon: charmander/HP = 17/MP = 10
Scratch(2 DMG), Ember(4 DMG, 5MP), Back
答案 0 :(得分：2)
主要问题是您没有正确使用or。
if(enemy_move == 1 or 2 or 3):
if(enemy_move == 4 or 5):
每次评估为True。这是因为逻辑0的布尔值为False，而任何其他数字的值为True
>>> bool(0)
False
>>> bool(1)
True
所以你的病情最终会成为。
if (enemy_move == 1 or True or True):
要正常工作，您需要比较每个值。
if(enemy_move == 1 or enemy_move == 2 or enemy_move == 3)
这可以通过各种方式进行清理，例如。
if enemy_move in (1, 2, 3):
if 1 <= enemy_move <= 3:
现在，除非您每次使用if
if/elif
然后，这将从头到尾按顺序检查每一个，如果一个评估为if enemy_move in (1, 2, 3):
...
elif enemy_move in (4, 5):
...
elif enemy_move == 6:
...
else:
...
，那么一旦条件满足，它将继续到下一个False。然后它不会做其余的事。
答案 1 :(得分：1)
if(enemy_move == 1 or 2 or 3):
检查enemy_move是否等于1，如果计算结果为false，则检查2是否为真值，它始终是。要检查值是否是三者中的任何一个，您需要进行三次比较，或者您可以使用in：
if enemy_move in (1, 2, 3):
或者您可以使用双面范围检查：
if 1 <= enemy_move < 4:
这是python，所以你不需要在if条件周围添加括号。
答案 2 :(得分：0)
，如：
...
if(enemy_move == 1 or 2 or 3):
...
if(enemy_move == 4 or 5):
...
if (enemy_move == 6):
...
请注意，只有前两个将始终一起执行，因为当if计算时，它检查[如果enemy_move等于1]或者如果[2]或[3]，则2和3应该是enemy_move == 2并且enemy_move == 3，如果你没有把敌人移动==＆＃39;它总是用if运算符计算为TRUE，这就是为什么只有最后一个运算符 ... if（enemy_move == 6）： ... 不要一起执行。
答案 3 :(得分：0)
当你使用随机时，你应该总是使用一个唯一的种子，否则生成的数字将始终是相同的
在您启动程序时设置一次种子
CREATE TABLE IF NOT EXISTS `shmarket`.`CITIES` (
`cityId` VARCHAR(6) NOT NULL,
`name` VARCHAR(45) NOT NULL,
`PROVINCES_provinceId` VARCHAR(6) NOT NULL,
PRIMARY KEY (`cityId`),
INDEX `fk_CITIES_PROVINCES1_idx` (`PROVINCES_provinceId` ASC),
CONSTRAINT `fk_CITIES_PROVINCES1`
FOREIGN KEY (`PROVINCES_provinceId`)
REFERENCES `shmarket`.`PROVINCES` (`provinceId`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
COLLATE = utf8_unicode_ci;
-----------------------------------------------------
Table `shmarket`.`USERS`
-----------------------------------------------------
CREATE TABLE IF NOT EXISTS `shmarket`.`USERS` (
`userId` INT NOT NULL AUTO_INCREMENT,
`name` VARCHAR(45) NOT NULL,
`surname` VARCHAR(45) NOT NULL,
`email` VARCHAR(45) NOT NULL,
`password` VARCHAR(45) NOT NULL,
`registryDate` TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
`role` VARCHAR(6) NOT NULL,
`CITIES_cityId` VARCHAR(6) NOT NULL,
PRIMARY KEY (`userId`),
UNIQUE INDEX `email_UNIQUE` (`email` ASC),
INDEX `fk_USERS_CITIES1_idx` (`CITIES_cityId` ASC),
CONSTRAINT `fk_USERS_CITIES1`
FOREIGN KEY (`CITIES_cityId`)
REFERENCES `shmarket`.`CITIES` (`cityId`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
你使用的种子并不重要，只要它变化。大多数人使用的最佳示例是当前时间戳。
random.seed( ... )
希望这会有所帮助
答案 4 :(得分：0)
我认为问题在于if语句 请勿使用if语句执行此操作：
if (enemy_move == 2 or 3 or 4):
您想要做的是以下内容：
if (enemy_move == 2 or enemy_move == 3 or enemy_move =-- 4)