我喜欢使用带有JQuery AJAX的PHP中的codeigniter Framework上传图像，而无需重定向页面。当我上传图像时，它会重定向到控制器区域并且值不会插入到数据库中，ajax响应也不会出现，
任何人都可以解决我的问题....提前致谢...
这是我的观看区域。
<form action="<?php echo site_url("Admin_Creator/do_upload")?>" enctype="multipart/form-data" accept-charset="utf-8" name="formname" id="frm_imageuupload" method="post">
<div class="form-group">
<label for="menu">Select Menu</label>
<select class="form-control" id="selectmenuid">
<option value="">-- Select Menu --</option>
<?php foreach($showData as $show):?>
<option value="<?php echo $show->menu_id?>"><?php echo $show->menu_name?></option>
<?php endforeach;?>
</select>
</div>
<div class="form-group">
<label for="menu">Select Sub Menu</label>
<select class="form-control" id="selectsubmenu">
<option>--Select Sub Menu--</option>
</select>
</div>
<div class="form-group">
<label for="imagetitle">Image Title</label>
<input type="text" class="form-control" name="imagetitle" id="imagetitle" placeholder="Enter Image Title" required="required">
</div>
<div class="control-group form-group">
<div class="controls">
<label>Upload Photo:</label>
<input name="file" type="file" id="image_file" required>
<p class="help-block"></p>
</div>
</div>
<button type="submit" class="btn btn-primary" id="submit">Submit</button>
</form>
这是我的Ajax编码
$('#submit').on('click',function(){
var inputFile=$('input[name=file]');
var fileToUpload=inputFile[0].files[0];
var other_data = $('#frm_imageuupload').serializeArray();
var formdata=new FormData();
formdata.append(fileToUpload);
formdata.append(other_data);
//now upload the file using ajax
$.ajax({
url:"<?php echo base_url('Admin_Creator/do_upload') ?>",
type:"post",
data:formdata,
processData:false,
contentType:false,
success: function(data){
if (data== 'true'){
window.location.reload();
}
else{
alert("Pls Try Again");
}
}
});
这是我的控制器编码......
public function do_upload(){
$config['upload_path']="./upload";
$config['allowed_types']='gif|jpg|png';
$this->load->library('upload',$config);
if($this->upload->do_upload()){
$data = array('upload_data' => $this->upload->data());
$data1 = array(
'menu_id' => $this->input->post('selectmenuid'),
'submenu_id' => $this->input->post('selectsubmenu'),
'imagetitle' => $this->input->post('imagetitle'),
'imgpath' => $data['upload_data']['file_name']
);
$result= $this->Admin_model->save_imagepath($data1);
if ($result == TRUE) {
echo "true";
}
}
}
这是我的模型编码
public function save_imagepath($data1)
{
$this->db->insert('images', $data1);
return $this->db->insert_id();
}
答案 0 :(得分：3)
试一试。它正在工作 -
HTML表单 -
<form enctype="multipart/form-data" id="submit">
<div class="form-group">
<label for="menu">Select Menu</label>
<select class="form-control" name="selectmenuid" id="selectmenuid">
<option value="">-- Select Menu --</option>
<?php foreach($showData as $show):?>
<option value="<?php echo $show->menu_id?>"><?php echo $show->menu_name?></option>
<?php endforeach;?>
</select>
</div>
<div class="form-group">
<label for="menu">Select Sub Menu</label>
<select class="form-control" name="selectsubmenu" id="selectsubmenu">
<option>--Select Sub Menu--</option>
</select>
</div>
<div class="form-group">
<label for="imagetitle">Image Title</label>
<input type="text" class="form-control" name="imagetitle" id="imagetitle" placeholder="Enter Image Title" required="required">
</div>
<div class="control-group form-group">
<div class="controls">
<label>Upload Photo:</label>
<input name="file" type="file" id="image_file" required>
<p class="help-block"></p>
</div>
</div>
<button type="submit" class="btn btn-primary" id="sub">Submit</button>
</form>
Ajax -
$('#submit').submit(function(e){
e.preventDefault();
$.ajax({
url:'Your path',
type:"post",
data:new FormData(this),
processData:false,
contentType:false,
cache:false,
async:false,
success: function(data){
alert(data);
}
});
});
只需在ajax中设置url，它就能完美运行 控制器功能 -
public function do_upload(){
$config['upload_path']="./upload";
$config['allowed_types']='gif|jpg|png';
$this->load->library('upload',$config);
if($this->upload->do_upload("file")){
$data = array('upload_data' => $this->upload->data());
$data1 = array(
'menu_id' => $this->input->post('selectmenuid'),
'submenu_id' => $this->input->post('selectsubmenu'),
'imagetitle' => $this->input->post('imagetitle'),
'imgpath' => $data['upload_data']['file_name']
);
$result= $this->Admin_model->save_imagepath($data1);
if ($result == TRUE) {
echo "true";
}
}
}
答案 1 :(得分：0)
$('form').on('submit',function(e){//bind event on form submit.
e.preventDefault();//stop submit
......... //your other codes
答案 2 :(得分：0)
这就是我解决这个问题的方法
<强> HTML
<div class="form-group">
<label for="logo">Service Provider Logo / Icon</label>
<input type="file" class="form-control" name="file" id="file" required="required">
<img src="#" id="img-logo" alt="image" class="img-responsive" style="height: 200px !important;">
<input type="hidden" class="" id="returned-sp-id">
</div>
<div class="form-group">
<label for="caption">Service Provider Name</label>
<input type="text" class="form-control" id="caption" required="required">
</div>
<div class="form-group">
<label for="details">Service Provider Details</label>
<textarea type="text" class="form-control" id="details" required="required"></textarea>
</div>
</form>
Jquery Ajax
$(function() {
$('#service-provider-details').on('submit', function(e){
var caption = $('#caption').val();
var details = $('#details').val();
var data = new FormData(this);
data.append('caption', caption);
data.append('details', details);
$.ajax({
url:'<?= base_url(), 'create_profile_sp/upload' ?>',
type:"post",
data: data,
processData:false,
contentType:false,
cache:false,
async:true,
success: function(data){
console.log(data);
}
});
e.preventDefault();
});
});
控制器
class Create_profile_sp extends CI_Controller
{
function __construct()
{
parent::__construct();
$this->load->model('profile_sp_m');
}
public function upload($data) {
$data = $_POST;
$this->profile_sp_m->upload_logo($data);
}
}
模型
class profile_sp_m extends CI_Model
{
public $_tablename = 'profiles';
function __construct()
{
// Call the Model constructor
parent::__construct();
}
public function upload_logo($data) {
$caption = $data['caption'];
$details = $data['details'];
if(isset($_FILES["file"]["type"]))
{
$validextensions = array("jpeg", "jpg", "png");
$temporary = explode(".", $_FILES["file"]["name"]);
$file_extension = end($temporary);
if ((($_FILES["file"]["type"] == "image/png") ||($_FILES["file"]["type"] == "image/jpg") ||
($_FILES["file"]["type"] == "image/jpeg") ) &&
($_FILES["file"]["size"] < 100000) &&
in_array($file_extension, $validextensions)){
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br/><br/>";
} else {
$sourcePath = $_FILES['file']['tmp_name']; Store source path in a variable
$targetPath = "uploads/profiles/" . $_FILES['file']['name']; // The Target path where file is to be stored
move_uploaded_file($sourcePath,$targetPath); // Moving Uploaded file
// The Image Data
$imageData = [
'caption' => $caption,
'description' => $details,
];
// Insert the data
$this->db->insert($this->_tablename, $imageData);
}
}
}
}
}