使用Java

Question

我目前正在使用Java进行RSA加密，我必须使用私有和公共模数进行加密。我目前有以下内容：

private void createPublicKey() throws NoSuchAlgorithmException, InvalidKeySpecException {
        String publicModulus = "d2c34017ef94f8ab6696dae66e3c0d1ad186bbd9ce4461b68d7cd017c15bda174045bfef36fbf048" +
                "73cfd6d09e3806af3949f99c3e09d6d3c37f6398d8c63f9a3e39b78a187809822e8bcf912f4c44a8" +
                "92fe6a65a477ddea9582738317317286a2610ba30b6b090c3b8c61ffb64207229b3f01afe928a960" +
                "c5a44c24b26f5f91";

        BigInteger keyInt = new BigInteger(publicModulus, 16);
        BigInteger exponentInt = new BigInteger("10001", 16);
        RSAPublicKeySpec keySpeck = new RSAPublicKeySpec(keyInt, exponentInt);
        KeyFactory keyFactory = KeyFactory.getInstance("RSA");
        publicKey = keyFactory.generatePublic(keySpeck);

    }

private void createPrivateKey() throws NoSuchAlgorithmException, InvalidKeySpecException {
        String privateModulus = "6c97ab6369cf00dd174bacd7c37e6f661d04e5af10670d4d88d30148ec188e63227b8dac0c517cf9" +
                "67aa73cd23684c9165dc269f091bfab33b6c5c7db95b54130e348255c30aaaac1c7f09ef701e0d6f" +
                "6dc142d2e4ed78466cc104e28d50be7adf3863afc021dbdd8b5f0b968b7cd965242c7d8d4b32ee84" +
                "0fac3cad134344c1";
        BigInteger privateModulusInt = new BigInteger(privateModulus, 16);
        BigInteger exponentInt = new BigInteger("10001", 16);
        RSAPrivateKeySpec privateKeySpec = new RSAPrivateKeySpec(privateModulusInt, exponentInt);
        KeyFactory factory = KeyFactory.getInstance("RSA");
        privateKey = factory.generatePrivate(privateKeySpec);
    }

在主要方法中，我有以下内容：

        createPrivateKey();
        createPublicKey();

        String data = "12";

        Cipher cipher1 = Cipher.getInstance("RSA/ECB/NoPadding");
        cipher1.init(Cipher.ENCRYPT_MODE, publicKey);
        byte[] encryptedData = cipher1.doFinal(data.getBytes());

        Cipher cipher2 = Cipher.getInstance("RSA/ECB/NoPadding");
        cipher2.init(Cipher.DECRYPT_MODE,privateKey);
        byte[] decryptedData = cipher2.doFinal(encryptedData);
        System.out.println(new String(decryptedData));

在控制台中我得到以下内容： .7 p;％kV 9y xa ɼ{而不是"12"如果我制作String data = "12345";，我然后得到：javax.crypto.BadPaddingException: Message is larger than modulus

首先为什么加密和解密不起作用？为什么我没有回来"12"。其次，为什么我的数据不能大于2个字符？

注意我正在使用以下website来获取模数和指数值。

Answer 1

创建私钥时出错。你提供公共指数而不是私人和（如评论@ dave_thomsom_085）私人指数而不是模数

使用

更改.smt

createPrivateKey()

出于安全原因，您也不应在没有填充的情况下使用原始RSA。使用private static PrivateKey createPrivateKey() throws NoSuchAlgorithmException, InvalidKeySpecException { String publicModulus = "d2c34017ef94f8ab6696dae66e3c0d1ad186bbd9ce4461b68d7cd017c15bda174045bfef36fbf048" + "73cfd6d09e3806af3949f99c3e09d6d3c37f6398d8c63f9a3e39b78a187809822e8bcf912f4c44a8" + "92fe6a65a477ddea9582738317317286a2610ba30b6b090c3b8c61ffb64207229b3f01afe928a960" + "c5a44c24b26f5f91"; String privateExponent = "6c97ab6369cf00dd174bacd7c37e6f661d04e5af10670d4d88d30148ec188e63227b8dac0c517cf9" + "67aa73cd23684c9165dc269f091bfab33b6c5c7db95b54130e348255c30aaaac1c7f09ef701e0d6f" + "6dc142d2e4ed78466cc104e28d50be7adf3863afc021dbdd8b5f0b968b7cd965242c7d8d4b32ee84" + "0fac3cad134344c1"; BigInteger privateExponenInt = new BigInteger(privateExponent, 16); BigInteger keyInt = new BigInteger(publicModulus, 16); RSAPrivateKeySpec privateKeySpec = new RSAPrivateKeySpec(keyInt, privateExponenInt); KeyFactory factory = KeyFactory.getInstance("RSA"); return factory.generatePrivate(privateKeySpec); } 或新的OAEP填充RSA/ECB/PKCS1Padding

根据this answer，您可以使用RSA/ECB/OAEPWithSHA1AndMGF1Padding数据加密，最多比密钥大小少11个字节。 and using OAEP它必须小于键模数的大小 - 41

然后，使用您的1024位密钥：

• PKCS1：PKCS1Padding
• OAEP：(1024 bits / 8) - 11 = 117 bytes

还建议直接使用CRT代替私有指数

(1024 bits / 8) - 42 = 86 bytes