Question

以下是我的代码，其计算错误，请问如何才能正确

控制器：

$q = 'Select sum(hours) as total_hours , client_projects.project_name  
      from client_projects join project_assignees 
      on (project_assignees.project_id = client_projects.project_id) 
      join daily_status on (daily_status.project_name = client_projects.project_name) 
      where client_projects.project_id = "'.$project_id.'" ';
$var = $this->project_model->q_single($q);

查看代码：

    <tr>
    <td>Total Hours </td>
    <td><?php $init = $working_hour['total_hours']; $hours = floor($init / 3600);
          $minutes = floor(($init / 60) % 60); $seconds = $init % 60; echo "$hours:$minutes:$seconds";?>
    </td>
    </tr>

我想计算一个特定项目的总工作时间并不知道我错在哪里请帮忙... 提前谢谢

Answer 1

它很长，但我希望它会帮助你

Select  concat(floor(SUM( TIME_TO_SEC( `hours` ))/3600),':',floor(SUM( TIME_TO_SEC( `hours` ))/60)%60,':',SUM( TIME_TO_SEC( `hours` ))%60) as total_hours from tablename

Answer 2

尝试查看UNIX_TIMESTAMP和SEC_TO_TIME。

您可以总结时间戳之间的差异，然后使用该值（以毫秒为单位）来获取时间：

请参阅以下示例

SELECT SEC_TO_TIME(time_milis / 1000)
FROM (
   SELECT SUM(UNIX_TIMESTAMP(date1) - UNIX_TIMESTAMP(date2)) as time_milis
   FROM table
)

如何在PHP

2 个答案: