Question

我正在尝试使用以下html和php代码将某些数据输入数据库...但显然无论我在运行代码时输入文本框，在数据库中输入为“1”...我该怎么做才能解决这个问题？

<html>
    <head>
        <title>Project Details</title>
    </head>
    <body>
      <?php include 'project.html';

       $pn=isset($_POST['name']) ? $_POST['ProjectName'] : ''; 
      $tn=isset($_POST['tname']) ? $_POST['TaskName'] : ''; 
     $dsc=isset($_POST['DESC']) ? $_POST['Proj_desc'] : '';
      $serverName = "Swagatha-PC"; 
         if($_SERVER['REQUEST_METHOD']=="POST")
        {
        $connectionInfo = array( "Database"=>"Testing");
        $conn = sqlsrv_connect( $serverName, $connectionInfo);

     if( $conn ) 
          {
 echo "Connection established.<br />";
  }
   else
     {
    echo "Connection could not be established.<br />";
    die( print_r( sqlsrv_errors(), true));
    } 

     $query="Insert Into dbo.Project (ProjectName,TaskName,Proj_desc) values ('$pn' ,'$tn' , '$dsc')";
       $stmt=sqlsrv_query($conn,$query);


     if($stmt==false)
      {
    echo "Error in adding Info!! Reload Page an try again!!<br/>";
         die( print_r( sqlsrv_errors(), true));
      }
    else
     {
    echo " Record Added!!";
     }
    sqlsrv_close($conn);

     }
     ?>
    </body>
       </html>

html代码是

 <html>
     <head>
         <title>Project Details</title>
     </head>
     <body>
         <form method = "post" action = "http://localhost/project.php">
             <table>
                 <tr>
                     <td>Project Name:</td> 
                     <td><input type = "text" name = "name"></td>
                 </tr>
                 <tr>
                     <td>Task Name:</td>
                     <td><input type = "text" name = "tname"></td>
                 </tr>
                 <tr>
                     <td>Project description:</td>
                     <td><textarea name = "DESC" rows = "5" cols = "40"></textarea></td>
                 </tr>
                 <tr>
                     <td><input type = "submit" name = "submit" value = "Submit" onclick="http://localhost/project.php"></td>
                 </tr>
             </table>
         </form>
     </body>
 </html>

我输入的数据在数据库中输入如下： Output error

如何修复此错误????

Answer 1

请更改

$pn=isset($_POST['ProjectName']);
$tn=isset($_POST['TaskName']);
$dsc=isset($_POST['Proj_desc']);

到

$pn=isset($_POST['name']) ? $_POST['name'] : '';
$tn=isset($_POST['tname']) ? $_POST['tname'] : '';
$dsc=isset($_POST['DESC']) ? $_POST['DESC'] : '';

PHP-Data没有输入数据库

1 个答案: