SQL Server：REPLACE逗号并将其与类似行组合

Question

我有一个错误的表结构。我尝试尽可能少地修改它，因为真正的问题更复杂。我在SQL Server 2005中工作。

这是我的表：

tbl_item

export PGPASSWORD=dbpass
psql --dbname=dbpass --username=dbuser --host=127.0.0.1 -c "COPY (SELECT * FROM widget) TO stdout DELIMITER ',' CSV HEADER" > export.csv

查询：

id | item
---+------
1  | car
2  | car
3  | car, => This is what I focus
4  | jet 
5  | jet, car => This is just an example of the comma purpose

结果：

SELECT item, count(*) AS sum 
FROM tbl_item 
GROUP BY item 
ORDER BY sum DESC

我想要的是这样的：

item    | sum
--------+-------
car     | 2
car,    | 1
jet     | 1 
jet,car | 1

我试过了：

item     | sum
---------+--------
car      | 3
jet      | 1 
jet, car | 1 => actually I don't care about this, but this just for example

但结果是：

SELECT REPLACE(item,',',''), count(*) AS sum 
FROM tbl_item 
GROUP BY item 
ORDER BY sum DESC

我可以用PHP操作这么简单，但我想知道如何使用纯SQL Server。

提前致谢！

Answer 1

尝试：

GROUP BY REPLACE(item,',','')

这将规范化项目，然后分组。

Answer 2

您需要将其添加到group by子句中：

SELECT REPLACE(item,',',''), count(*) AS sum 
FROM tbl_item 
GROUP BY replace(item,',','')
ORDER BY sum DESC