Question

我需要创建如下所示的XML：

<record id="100000000000000000" type="Message">  
    ...a bunch of xml ...
</record>

相反，使用我正在使用的FSsharp代码，我得到了这个：

<record>
    <type>Message</type>
    <id>118448</id>
    ...a bunch of xml....
</record>

这就是我目前正在做的事情：

type record( id:int, sr:sender, recipients: recipient array, atts : attachment array, con : conversation, madeDate : creation) =  
    let mutable id: int = id
    let mutable typ = "Message"
    let mutable creation = madeDate
    let mutable sender  = sr
    let mutable recipients = recipients
    let mutable conversation = con
    let mutable attachments = atts

    public new() =
        record( -1, sender(-1,"Joe","Plumber","Joe@plumber.com"), Array.empty, Array.empty, conversation(), creation())    

    [<XmlElement("type")>] 
    member this.Type with get() = typ and set v = typ <- v

    [<XmlElementAttribute("id")>] 
    member this.Id with get() = id and set v = id <- v

    [<XmlElement("creation")>] 
    member this.Creation with get() = creation and set v = creation <- v

    [<XmlElement("sender")>]
    member this.Sender with get() = sender and set v = sender <- v

    [<XmlArrayAttribute("recipients")>]
    [<XmlArrayItem(typeof<recipient>, ElementName = "recipient")>]
    member this.Recipients with get() = recipients and set v = recipients <- v   

    [<XmlElement("conversation_info")>]
    member this.Conversation with get() = conversation and set v = conversation <- v

    [<XmlArrayAttribute("attachments")>]        
    [<XmlArrayItem(typeof<attachment>, ElementName = "attachment")>]
    member this.Attachments with get() = attachments and set v = attachments <- v

Answer 1

我认为你想要XmlAttributeAttribute而不是XmlElementAttribute。

请注意

[<XmlElement>]

和

[<XmlElementAttribute>]

是一样的（就像C＃一样）。

如何使用FSharp创建XML属性（而不是元素）？

1 个答案: