Question

我的文本文件包含不同的字符串，每个字符串都在一个单独的行中，如

1
2
3

我需要一个C＃代码来获取输入和输出文件，读取文本输入并用逗号替换断行，这样输出文件应该包含运行代码后的1,2,3

Answer 1

写一些像这样的代码

for each line in the file
  add line to a stringbuilder
  add, to stringbuilder

write stringbuilder.ToString() to new text file

Answer 2

string line;
var str=new List<string>();
// Read the file and display it line by line.
System.IO.StreamReader file = new System.IO.StreamReader("c:\\test.txt");
while((line = file.ReadLine()) != null)
{
   str.Add(line);
}

file.Close();

return string.Join(",",str);

看这里：

https://msdn.microsoft.com/en-CA/library/aa287535(v=vs.71).aspx

Answer 3

借用这个答案：C#: How to read lines from text file and output them split by comma in another text file

using (TextFieldParser parser = new TextFieldParser(@"c:\temp\test.txt")) 
{
    parser.TextFieldType = FieldType.Delimited;
    parser.SetDelimiters("\n");
    string csvData = "";
    while (!parser.EndOfData) 
    {
        //Processing row
        string[] fields = parser.ReadFields();
        foreach (string field in fields) 
        {
            csvString += field + ",";
        }
        csvString += "\n";
    }
}

其中csvString是你的答案

Answer 4

如果文件相对较小，那么可能是一个单行解决方案？

File.WriteAllText (@"c:\path\file2.txt", String.Join (",", File.ReadAllLines(@"c:\path\file1.txt")));

C＃：如何从文本文件中读取行，并在另一个文本文件中输出用逗号分割的行

4 个答案: