我在JS中制作了一个简单的Lissajous图形生成器。 我无法在html代码中显示当前滑块值。 这是完整的代码:
<!doctype html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css" media="screen" />
<meta charset="UTF-8">
<title>Lissajous figures</title>
<br>
<script type="application/javascript">
var ctx;
var timer = null;
var aS = new Array();
var rad = 189;
var max=3*360, m1=max-1, m2 = max/2;
var iXo=0, iYo=m2/2;
var parN=2, parM=1;
function init() {
var canvas = document.getElementById("field");
if (canvas.getContext) { ctx = canvas.getContext("2d");
sf=Math.sin(3.14159265/m2); cf=Math.cos(3.14159265/m2);
s=-sf; c=cf;
for (i=0; i<m2; i++) {
s1=s*cf+c*sf; c=c*cf-s*sf; s=s1;
aS[i]=Math.round(rad*(1.+s))+1;
aS[i+m2]=Math.round(rad*(1.-s))+1;
}
startAnimation();
}
}
function draw() {
Xo=aS[iXo],Yo=aS[iYo];
ctx.beginPath();
ctx.moveTo(Xo,Yo);
for (j=max; j>0; j--) {
iX=(iXo+parM) % max; iY=(iYo+parN) % m1;
X=aS[iX]; Y=aS[iY];
ctx.lineTo(X,Y);
iXo=iX; iYo=iY; Xo=X; Yo=Y;
}
ctx.clearRect (0, 0, 500, 500);
ctx.stroke();
ctx.strokeStyle="green";
ctx.lineWidth = 3;
}
function startAnimation() {
setInterval(draw,0);
}
</script>
</head>
<h1>Lissajous Figure Generator</h1>
<br>
<body onload="init();" bgcolor="black">
<center><canvas id="field" width="400" height="400">
</canvas>
<br>
<br>
<br>
<h2>Choose parameters value using sliders below:</h2>
<p><h2>A = <input type="range" id="value1" name="parM_choose" min="1" max="9" value="1" step="1" oninput="parM=parseInt(this.value)">
<output name="show_parM_val" id="parM">1</output></h2>
</p>
<p><h2>B = <input type="range" id="value2" min="1" max="9" value="2" step="1" oninput="parN=parseInt(this.value)">
<output name="show_parN_val" id="parN">2</output></h2>
</p>
</center>
</body>
</html>
如何使输出值有效?什么应该是正确的ID? 我在谈论下面的代码片段:
<h2>Choose parameters value using sliders below:</h2>
<p><h2>A = <input type="range" id="value1" name="parM_choose" min="1" max="9" value="1" step="1" oninput="parM=parseInt(this.value)">
<output name="show_parM_val" id="parM">1</output></h2>
</p>
<p><h2>B = <input type="range" id="value2" min="1" max="9" value="2" step="1" oninput="parN=parseInt(this.value)">
<output name="show_parN_val" id="parN">2</output></h2>
答案 0 :(得分:2)
您的问题是您在幻灯片中设置全局范围变量,但在代码中使用局部变量,请查看此更新的工作示例:
<!doctype html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css" media="screen" />
<meta charset="UTF-8">
<title>Lissajous figures</title>
<br>
<script type="application/javascript">
var ctx;
var timer = null;
var aS = new Array();
var rad = 189;
var max = 3 * 360,
m1 = max - 1,
m2 = max / 2;
var iXo = 0,
iYo = m2 / 2;
parN = 2;
parM = 1;
function init() {
var canvas = document.getElementById("field");
if (canvas.getContext) {
ctx = canvas.getContext("2d");
sf = Math.sin(3.14159265 / m2);
cf = Math.cos(3.14159265 / m2);
s = -sf;
c = cf;
for (i = 0; i < m2; i++) {
s1 = s * cf + c * sf;
c = c * cf - s * sf;
s = s1;
aS[i] = Math.round(rad * (1. + s)) + 1;
aS[i + m2] = Math.round(rad * (1. - s)) + 1;
}
startAnimation();
}
}
function draw() {
Xo = aS[iXo], Yo = aS[iYo];
ctx.beginPath();
ctx.moveTo(Xo, Yo);
for (j = max; j > 0; j--) {
iX = (iXo + parM) % max;
iY = (iYo + parN) % m1;
X = aS[iX];
Y = aS[iY];
ctx.lineTo(X, Y);
iXo = iX;
iYo = iY;
Xo = X;
Yo = Y;
}
ctx.clearRect(0, 0, 500, 500);
ctx.stroke();
ctx.strokeStyle = "green";
ctx.lineWidth = 3;
}
function startAnimation() {
setInterval(draw, 0);
}
</script>
</head>
<h1>Lissajous Figure Generator</h1>
<br>
<body onload="init();" bgcolor="black">
<center>
<canvas id="field" width="400" height="400">
</canvas>
<br>
<br>
<br>
<div style="background: #999;">
<h2>Choose parameters value using sliders below:</h2>
<p>
<h2>A = <input type="range" id="value1" name="parM_choose" min="1" max="9" value="1" step="1" oninput="document.getElementById('parM').innerText = parseInt(this.value);parM=parseInt(this.value)">
<output name="show_parM_val" id="parM">1</output></h2>
</p>
<p>
<h2>B = <input type="range" id="value2" min="1" max="9" value="2" step="1" oninput="document.getElementById('parN').innerText = parseInt(this.value);parN=parseInt(this.value)">
<output name="show_parN_val" id="parN">2</output></h2>
</p>
</div>
</center>
</body>
</html>
答案 1 :(得分:1)
这很有效。 使用函数updateTextInput(val)函数定位元素以更新字段中的值。 在这里回答:HTML5 input type range show range value
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css" media="screen" />
<meta charset="UTF-8">
<title>Lissajous figures</title>
<br>
<script type="application/javascript">
var ctx;
var timer = null;
var aS = new Array();
var rad = 189;
var max=3*360, m1=max-1, m2 = max/2;
var iXo=0, iYo=m2/2;
var parN=2, parM=1;
function init() {
var canvas = document.getElementById("field");
if (canvas.getContext) { ctx = canvas.getContext("2d");
sf=Math.sin(3.14159265/m2); cf=Math.cos(3.14159265/m2);
s=-sf; c=cf;
for (i=0; i<m2; i++) {
s1=s*cf+c*sf; c=c*cf-s*sf; s=s1;
aS[i]=Math.round(rad*(1.+s))+1;
aS[i+m2]=Math.round(rad*(1.-s))+1;
}
startAnimation();
}
}
function draw() {
Xo=aS[iXo],Yo=aS[iYo];
ctx.beginPath();
ctx.moveTo(Xo,Yo);
for (j=max; j>0; j--) {
iX=(iXo+parM) % max; iY=(iYo+parN) % m1;
X=aS[iX]; Y=aS[iY];
ctx.lineTo(X,Y);
iXo=iX; iYo=iY; Xo=X; Yo=Y;
}
ctx.clearRect (0, 0, 500, 500);
ctx.stroke();
ctx.strokeStyle="green";
ctx.lineWidth = 3;
}
function startAnimation() {
setInterval(draw,0);
}
function updateTextInput(val) {
document.getElementById('textInput').value=val;
}
function updateTextInput2(val) {
document.getElementById('textInput2').value=val;
}
</script>
</head>
<h1>Lissajous Figure Generator</h1>
<br>
<body onload="init();" bgcolor="black">
<center><canvas id="field" width="400" height="400">
</canvas>
<br>
<br>
<br>
<h2>Choose parameters value using sliders below:</h2>
<p><h2>A = <input type="range" id="value1" name="parM_choose" min="1" max="9" value="1" step="1" oninput="parM=parseInt(this.value)" onchange="updateTextInput(this.value);">
<input type="text" id="textInput" value="">
</p>
<p><h2>B = <input type="range" id="value2" min="1" max="9" value="2" step="1" oninput="parN=parseInt(this.value)" onchange="updateTextInput2(this.value);">
<input type="text" id="textInput2" value="">
</p>
</center>
</body>
</html>