我有一个用Kivy创建的弹出窗口,其中包含2个按钮。用户可以通过按弹出区域外部(auto_dismiss = True)或单击“否”按钮来关闭弹出窗口。 选择“是”按钮将退出整个应用程序。
请参阅相关代码:
class ExitApp(App):
def exit_confirmation(self):
# popup can only have one Widget. This can be fixed by adding a BoxLayout
self.box_popup = BoxLayout(orientation = 'horizontal')
self.box_popup.add_widget(Label(text = "Really exit?"))
self.box_popup.add_widget(Button(
text = "Yes",
on_press = ExitApp.exit,
size_hint = (0.215, 0.075)))
self.box_popup.add_widget(Button(
text = "No",
on_press = self.popup_exit.dismiss,
size_hint=(0.215, 0.075)))
self.popup_exit = Popup(title = "Exit",
content = self.box_popup,
size_hint = (0.4, 0.4),
auto_dismiss = True)
self.popup_exit.open()
def exit(self):
App.get_running_app().stop()
问题现在按下“否”按钮。按下该按钮后,代码将退出并显示以下错误:
on_press = self.popup_exit.dismiss,
AttributeError:'Button'对象没有属性'popup_exit'
我知道如何尽可能轻松地解决这个问题吗?
答案 0 :(得分:1)
您可以通过延迟函数解决此问题
on_press = lambda *args: self.popup_exit.dismiss()
这样,当按下按钮并且 popup_exit 已经到位时,查找将仅 ...
答案 1 :(得分:0)
将on_press = self.popup_exit.dismiss
更改为on_press = lambda: self.popup_exit.dismiss()
,因为dismiss是一个函数,需要在按下按钮时调用。
def exit_confirmation(self):
# popup can only have one Widget. This can be fixed by adding a BoxLayout
self.box_popup = BoxLayout(orientation = 'horizontal')
self.box_popup.add_widget(Label(text = "Really exit?"))
self.box_popup.add_widget(Button(
text = "Yes",
on_press = ExitApp.exit,
size_hint = (0.215, 0.075)))
self.popup_exit = Popup(title = "Exit",
content = self.box_popup,
size_hint = (0.4, 0.4),
auto_dismiss = True)
self.box_popup.add_widget(Button(
text = "No",
on_press = lambda: self.popup_exit.dismiss() ,
size_hint=(0.215, 0.075)))
self.popup_exit.open()
答案 2 :(得分:0)
在kivy
中可以进行这种工作吗?
on_press : root.dismiss()
答案 3 :(得分:-1)
试试这个:on_press = self.popup.dismiss()
代替on_press = self.popup_exit.dismiss