我需要在工作表上放置多个Checkbox。 Excel FormControl和ActiveX控件中的标准复选框选项太小。所以,我找到了使用this
链接的解决方法。
基本上,您将创建一个ActiveX标签,格式为Wingdings字体。当用户点击标签时,宏基本上将字符从空框Wingdings Chr(168)更改为复选框Wingdings Chr(254)。
如果手动创建标签并添加代码,一切正常。但我正在创建这些标签并使用VBA添加相应的Click事件代码。标签和代码正在创建,但它没有按照预期的方式显示Chr(168)。创建后,如果单击任何标签并转到其属性并单击字体,将打开字体窗口。即使你在这个窗口上没有做任何事情(因为字体已经使用VBA设置)并关闭它,标签将正确显示Chr(168)。
这是我的代码:
Public Function AddChkBox()
Dim sLabelName As String
Dim i As Integer
For i = 2 To 4 '~~> Actual number is big
sLabelName = "Label" & (i - 1)
With Sheets("Input").OLEObjects.Add(ClassType:="Forms.Label.1", Link:=False, _
DisplayAsIcon:=False, Left:=Range("B" & i).Left + 5, _
Top:=Range("B" & i).Top + 3, Width:=60, Height:=13)
.Name = sLabelName
.Object.Font.Name = "Wingdings"
.Object.Font.Size = 16
.Object.Caption = Chr(168)
.Object.TextAlign = fmTextAlignCenter
End With
Call InsertSub("Input", sLabelName, "Click")
Next
End Function
Public Function InsertSub(shtName As String, labelName As String, action As String)
' Code courtesy @Siddharth Rout
Dim wb As Workbook, ws As Worksheet
Dim VBP As Object, VBC As Object, CM As Object
Dim strProcName As String
strProcName = labelName & "_" & action
Set wb = ThisWorkbook
Set ws = wb.Sheets(shtName)
Set VBP = wb.VBProject
Set VBC = VBP.VBComponents(ws.CodeName)
Set CM = VBC.CodeModule
With wb.VBProject.VBComponents( _
wb.Worksheets(ws.Name).CodeName).CodeModule
.InsertLines Line:=.CreateEventProc(action, labelName) + 1, _
String:=vbCrLf & _
" If " & labelName & ".Caption = Chr(254) Then" & vbCrLf & _
" 'box with no checkmark" & vbCrLf & _
" " & labelName & ".Caption = Chr(168)" & vbCrLf & _
" " & labelName & ".ForeColor = -2147483640" & vbCrLf & _
" Else" & vbCrLf & _
" 'box with a checkmark" & vbCrLf & _
" " & labelName & ".Caption = Chr(254)" & vbCrLf & _
" " & labelName & ".ForeColor = 32768" & vbCrLf & _
" End If"
End With
End Function
对此的任何想法......?
答案 0 :(得分:2)
您没有更改字体Charset
,Wingdings无法使用默认字符集。只需将其更改为2就可以了。
//......
.Name = sLabelName
.Object.Font.Name = "Wingdings"
'/ Need to add the charset. Default is 1. Change it to 2.
.Object.Font.Charset = 2
.Object.Font.Size = 16
//......
Charset - > 1 = DEFAULT_CHARSET
Charset - > 2 = SYMBOL_CHARSET