我成功运行了一个查询,选择了information_schema中表的列名,但是如果我在存储过程中运行相同的查询以将其与游标一起使用,那么information_schema是未知的。谁能告诉我原因并帮助我解决问题?谢谢 这是查询
SELECT column_name
FROM information_schema.columns
WHERE table_schema = 'database_name'
AND table_name='Table_name';
这是程序。
DELIMITER $$
CREATE PROCEDURE build_column_names_str (INOUT column_list varchar(4000))
BEGIN
DECLARE v_finished INTEGER DEFAULT 0;
DECLARE v_column varchar(100) DEFAULT "";
-- declare cursor for column names
DEClARE column_cursor CURSOR FOR
SELECT column_name
FROM information_schema.columns
WHERE table_schema = 'database_name'
AND table_name='Table_name';
-- declare NOT FOUND handler
DECLARE CONTINUE HANDLER
FOR NOT FOUND SET v_finished = 1;
OPEN column_cursor;
get_column: LOOP
FETCH column_cursor INTO v_column;
IF v_finished = 1 THEN
LEAVE get_column;
END IF;
-- build column name list
SET column_list = CONCAT(v_column,",",column_list);
END LOOP get_column;
CLOSE column_cursor;
END$$
DELIMITER ;
SET @column_list = "";
CALL build_column_names_str(@column_list);
SELECT @column_list;
由于
答案 0 :(得分:1)
您的代码是正确的。
检查程序执行的权限
或用
SELECT airportname, COUNT(DISTINCT foundBag.id) countFound, COUNT(DISTINCT lostBag.id) countLost
FROM airports
INNER JOIN foundBag ON airport_id = foundBag.airportDest
INNER JOIN lostBag ON airport_id = lostBag.airportDest
GROUP BY airport.airportname");
答案 1 :(得分:0)
我对information_schema.tables
也有类似的问题:当我在存储过程中调用information_schema.tables
时,它为所有字段返回NULL,并且更奇怪的是,存储过程中的另一个表又从另一个表中进行选择还会为每个字段返回NULL。
我通过在WHERE TABLE_SCHEMA = DATABASE()
的SELECT中添加information_schema.tables
来解决了这个问题