Question

继承人的问题，我有一个数据库，可以保存标记图像的信息：

我正在通过ajax调用将数据保存为对象，并将数据保存为对象，因此我可以检查标记的位置类型并为该类型的位置放置适当的标记。

我正在恢复数据正常，但当我尝试将数据添加到构造函数中以获取新的谷歌地图图像时出错了，我已经检查了警告说正确的信息在那里，它是如此给出了什么？

// the following code will wor!!!
                   new google.maps.Size(32,37) // The Size works
//The following line breaks it with dynamic value    
                   new google.maps.Size(myIconArray.icon[myData.name_etp].size)

继承人的完整代码：（静态代码行中的测试值与存储在我正在制作的对象引用中的值相同） http://www.focus-on-plants.com/locator_iconed.php

function addMarker(map, myData){
      console.log(myData)
      // Create the marker
      // create the marker info first
      myLatLng = new google.maps.LatLng(myData.lat_mdt, myData.lng_mdt);
      markersArray.push(myLatLng);
      markersInfoArray.push(myData);

      // ----------------------------
      // NOW CREATE THE ACTUAL ICON
       //alert( myIconArray.icon[myData.name_etp].size)

      /*var iconimage = new google.maps.MarkerImage(
       '/images/icons/markers/flower_lb/image_med.png', //myIconArray.icon[myData.name_etp].image,
       new google.maps.Size(myIconArray.icon[myData.name_etp].size) // The Size
       //new google.maps.Point(myIconArray.icon[myData.name_etp].origin), // The origin
       //new google.maps.Point(myIconArray.icon[myData.name_etp].anchorpoint) // The anchor
      );*/
      //console.log(iconimage)
      var iconshape = {
       type: 'poly',
       coord: [0,2,1,2,1,1,18,0,18,1,19,2,20,19,19,19,18,21,14,21,10,26,5,21,1,21,1,20,0,20,0,2]
      }

      //alert(myIconArray.shape[myData.name_etp])
      mySize = 'new google.maps.Size('+myIconArray.icon[myData.name_etp].size+')'
      var iconimage = new google.maps.MarkerImage(
       myIconArray.icon[myData.name_etp].image,
       // the following code works!!!
                        new google.maps.Size(32,37) // The Size works
                       //The following line breaks iot with dynamic value    
                       //new google.maps.Size(myIconArray.icon[myData.name_etp].size) 


       //new google.maps.Point(0, 0), // The origin
       //new google.maps.Point(13,29) // The anchor
      );
      var iconshadow = new google.maps.MarkerImage(
       '/images/icons/markers/flower_lb/shadow_med.png',
       new google.maps.Size(42,18), // The Size
       new google.maps.Point(0,0), // The origin
       new google.maps.Point(13,18) // The anchor
      );

      var marker = new google.maps.Marker({
       position: myLatLng,
       map: map,
       title: myData.name_mdt,
       icon: iconimage,
       shadow: iconshadow//,
       //shape: iconshape
      });

      // Wrapping the event listener inside an anonymous function
      // that we immediately invoke and passes the variable i to.
      (function(myData, marker) {
       // Creating the event listener. It now has access to the values of
       // myData and marker as they were during its creation
       google.maps.event.addListener(marker, 'click', function() {
        //create thecontent for the infowindow
        var content = createContent(myData);
        var infowindow = new google.maps.InfoWindow({
         content: content
        });
        infowindow.open(map, marker);
       });
      })(myData, marker);  

     };

Answer 1

好的，所以我发现了为什么会这样，

我正在通过new google.maps.Size(myIconArray.icon[myData.name_etp].size)

google image maps.size需要两个单独的参数new google.maps.Size(42,18)

我正在传递32, 37，这实际上是一个字符串，

我需要使用以下内容拆分字符串：

tmp = myIconArray.icon[myData.name_etp].size.split(",")

然后为我使用的尺寸添加x和y：new google.maps.Size(tmp[0], tmp[1])

谷歌地图v3动态设置标记大小

1 个答案: