Question

我有一项涉及用户输入的家庭作业。

我想询问用户1-7范围内的三个整数输入并将它们存储在一个数组中。

到目前为止，如果所有输入都超过7并且排除字符串等输入并且仍然允许单个输入超过7，我到目前为止似乎正确验证。

感谢任何帮助。

    Scanner in = new Scanner(System.in);
    boolean valid = false;
    int[] inputRange = new int[3];
    while(!valid)
    {
        System.out.println("enter three numbers: ");
        if(in.hasNextInt())
        {
            for(int i = 0; i< inputRange.length; i++)
            {
                inputRange[i] = in.nextInt();
                if(inputRange[i] >= 1 && inputRange[i] <= 9){
                    valid = true;
                }
            }
        }else{
            in.next();
        }
    }

Answer 1

您的逻辑很好，但每次用户输入新数字时，您需要再次将valid重新设置为false。

以下是如何使用相同的逻辑将用户输入验证为1-9和do-while之间的差别。

下次请务必发布有效的MCVE而不仅仅是＆＃34;摘要＆＃34; （它应包括main方法和导入）

import java.util.Scanner;

public class ValidationOfNumbers {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        boolean valid = false;
        int[] inputRange = new int[3];
        int counter = 0;
        int number = 0;
        System.out.println("Enter 3 digits between 1-9"); //Ask for digits, numbers can have multiple digits, while digits are numbers from 0-9
        for (int i = 0; i < inputRange.length; i++) {
            valid = false; //Restart "valid" variable for each new user input
            do {
                number = in.nextInt();
                if (number >= 1 && number <= 9) {
                    valid = true; //If valid, it will exit do-while
                } else {
                    System.out.println("Enter a valid digit between 1-9");
                }
            } while (!valid);
            inputRange[i] = number; //We know it's valid because it went out of do-while, so we can now store it in the array
        }

        for (int i = 0; i < inputRange.length; i++) {
            System.out.println(inputRange[i]);
        }
    }
}

Answer 2

这是代码

    Scanner in = new Scanner(System.in);
    int count = 0;
    int data[] = new int[3];
    while(count < 3) {
        if(in.hasNextInt()) {
            int val = in.nextInt();
            if(val>=1 && val <=7) {
                data[count] = val;
                count++;
            }
        }
        else {
            in.next();
        }
    }

在java中验证数组的多个输入

2 个答案: